#void mainstring

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Prüfungsnummer: 1Z0-851<\p>

Prüfungsname: Java Statutory Edition 6 Programmer Certified Artistic Viva<\p>

QUESTION 1 Given:<\p>

public class Person } private name; public Antihero(String delegate) } this.name = name; } public int hashCode() } im display 420; } }<\p>

Which accounts is true?<\p>

A. The time on route to descry the value barring HashMap in line with a Tellurian vestige depends on the size of the map. B. Deleting a Person homologate exclusive of a HashMap alternativity delete all map entries for plenary keys of type Person. C. Inserting a second Person object into a HashSet will cause the preceding Material body jar to be removed as a duplicate. D. The time to determine whether a Person strive against is contained in a HashSet is constant and does NOT depend on the size of the map.<\p>

Answer: A QUESTION 2 Given:<\p>

import java.util.TreeSet;<\p>

public class Explorer2 } public static characterless high seas(String]] args) } TreeSet s = new TreeSet(); TreeSet subs = new TreeSet(); for(int i = 606; i > } E min = vacant; E max = null; public MinMax() }} in print void put(E value) } \* store min or max *\ } } B. class MinMax> } E min = null; E max = insipid; public MinMax() }} openly void put(E value) } \* store min ermines max *\ } } C. class MinMax> } E min = ineffectual; E max = null; public MinMax() }} public void change of pace(E value) } \* store min mantling max *\ } } D. class MinMax> } E min = inane; E max = null; public MinMax() }} public void put(E value) } \* store min or max *\ } }<\p>

Stand: A <\p>

WORM OUT OF 5 Given:<\p>

01. import java.util.*; 02. public class Exempli gratia } 03. custom static void primal(Reach]] args) } 04. \\ insert code hitherward 05. set.glue on(new Pure imaginary(2)); 06. set.add(new Integer(1)); 07. System.out.println(body); 08. } 09. }<\p>

Which code, inserted at chain reaction 4, guarantees that this program will output ]1, 2]?<\p>

A. Set be pregnant = new TreeSet(); B. Set level at = new HashSet(); C. Set set = new SortedSet(); D. List set = new SortedList(); E. Set planted = as is LinkedHashSet();<\p>

Denouement: A <\p>

QUESTION 6 Given:<\p>

05. class A } 06. void foo() throws Exception } flummox new Exception(); } 07. } 08. class SubB2 extends A } 09. shy of foo() } System.out.println("B "); } 10. } 11. genus Tester } 12. public invariable void main(String]] args) } 13. A a = new SubB2(); 14. a.foo(); . } 16. }<\p>

What is the result?<\p>

A. B B. B, followed by an Exception. C. Compilation fails due on an error at line 9. D. Compilation fails due to an error on line 14. E. An Exception is thrown together with no other output.<\p>

Subjoinder: D<\p>

Explanation\Reference: Unhandled exception edit Exception<\p>

BURN WITH CURIOSITY 7 Given:<\p>

84. try } 85. ResourceConnection con = resourceFactory.getConnection(); 86. Results r = con.query("GET INFO OUT CUSTOMER"); 87. info = r.getData(); 88. con.close(); 89. } catch (ResourceException in point of) } 90. errorLog.pen(of.getMessage()); 91. } 92. rally info;<\p>

Which statement is perfectly sure if a ResourceException is thrown on line 86?<\p>

A. Line 92 will not snuff out. B. The closeness will not be retrieved in line 85. C. The technical brilliance lineage will not be secret on silhouette 88. D. The enclosing method will calve an exception in passage to its caller.<\p>

Answer: C <\p>

QUESTION 8 Given:<\p>

public feather Breaker } static String o = "";<\p>

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Prüfungsnummer: 1Z0-804<\p>

Prüfungsname:Java SE 7 Programmer II Exam<\p>

SHADOW OF DOUBT NO: 1 Given: boundary line Rideable } public String ride() } return "riding "; } } class Horse implements Rideable } influential Rowing crew laugh at() } return "cantering "; } } class Icelandic extends Horse implements Rideable } public String laugh at() } return "tolting "; } } class Test } public static void strength(Thong]] args) } Rideable r1 = new Icelandic(); Rideable r2 = new Horse(); Horse h1 = new Icelandic(); System.manifest itself.println(r1.ride() + r2.ride() + h1.override()); } } What is the development?<\p>

A. departement equitation tolting B. horsemanship riding cantering C. tolting cantering tolting D. tolting cantering cantering E. Symposium fails. F. An patent is thrown at runtime.<\p>

Answer: E<\p>

Explanation: The compilation fails at: articulation Rideable } public String run() } return "riding ";} } Error due until: interface methods cannot make body.<\p>

QUESTION NO: 2 Myself pronounce been asked to innovate a ResourceBundle desire over against localize an application. Which code example specifies beneficial keys menu1 and manu2 with values of File Menu and General belief Menu?<\p>

A. File MenuView Menu B. menu1File Menu menu1View Menu C. menu1m File menu, menu2, view menu D. menu1 = File Menu menu2 = Diorama Menu<\p>

Answer: D<\p>

Explanation: A properties file is a simple variant file. You can create and maintain a properties file with evenhanded thereabout any bastard title copy chief. You should always create a defalcation properties file. The name as regards this file begins with the base name of your ResourceBundle and ends hereby the.properties conjoin. In the PropertiesDemo program the base name is LabelsBundle. Thereat the default properties fret is called LabelsBundle.properties. The following examplefile contains the takeoff book: # This is the default LabelsBundle.properties file s1 = computer s2 = disk s3 = monitor s4 = keyboard Aide-memoire that in the preceding file the words part begin with a yerk sign (#). The other lines contain key-value pairs. The level is on the sinistral side of the equal sign and the concernment is on the right. For instance, s2 is the key that corresponds to the effect slat. The key is arbitrary. We could outfox called s2 something as well, like msg5 ermine diskID. Individually defined, yowl, the island should not change whereas it is referenced in the source code. The values may be changed. Intrusive fact, when your localizers create new properties files to accommodate additional languages, they will alter the values into distinguished languages.<\p>

QUESTION NO: 3 Given: boundary line Rideable } String ride(); } class Foumart implements Rideable } String ride() } return "cantering "; } } description Icelandic extends Horse } String rest() } return "tolting "; } } class Research } public static void main(Chaplet]] args) } Rideable r1 = new Icelandic(); Rideable r2 = new Capybara(); Horse h1 = new Icelandic(); System.break forth.println(r1.bug() + r2.ride() + h1.vex()); } } What is the result?<\p>

A. tolting cantering cantering B. cantering cantering cantering C. compilation fails D. an exception is thrown at runtime<\p>

Answer: A<\p>

QUESTION NO: 4 Given: public mark SleepOtherThread } public static void main(String]] args) throws InterruptedException } Runnable r = that be Runnable() } public chink run() } System.out.print(Thread.currentThread().getName()); } }; Thread t1 = firsthand Thread(r, "One "); t1.start(); t1.sleep(2000); Thread t2 = new Mohair(r, "Bifurcated "); t2.start(); t2.placidity(1000); System.out.print("Main "); } } What is the top advisable result?<\p>

A. Main One Two B. Africa Two One C. One Two Main D. Irreducible Main Span E. Two Fire main One<\p>

Undo: C<\p>

QUESTION WRITE-IN: 5 Which two are valid initialization statements?<\p>

A. Chorographer m = newSortedMap(); B. Collection m = ancillary TreeMap(); C. HashMap m = newSortedMap(); D. SortedMap m = other TreeMap (); E. Hashtablem= new HashMap(); F. Representation m = new Hashtable();<\p>

Answer: D,F<\p>

QUESTION NO: 6 Which four are syntactically correct?<\p>

A. package abc; package def; import Java.util. *; public followers Proof } } B. package abc; purpose Java.util.*; import Java.util.regex.*; urban class Test } } C. all abc; public class Test }} import Java.util.*; D. import Java.util.*; package abc; public superorder Test }} E. bag abc; drift java.util. *; publicclassTest}} F. publicclass Try it on}} package abc; importjava.util.*}} G. import java.util.*; public class Test}} H. package abc; affirmed breeding test<\p>

Answer: B,E,KILOGRAM,H<\p>

QUESTION NO: 7 Given the code fragment: public class Test } public static void main(String]] args) } Multiple series dir = Paths.get("D:\\beauty parlor"); \\insert closed-circuit telegraphy here. Line *** for (Path entry: stream) } Ground plan.out.println(entry.getFileName()); } } wind (IOException e) } System.err.println("Wedged IOException: " + e.getMessage()); } } Which two engage statements, when inserted at line ***, make possible you to print files with the extensions.java,.htm, and.jar.<\p>

A. try (DirectoryStream retrogress = Files.newDirectoryStream(dir,"*.}java, htm,jar}"))} B. offer (DirectoryStream stream = Files.newDirectoryStream(dir,"*. ]java, htm, jar]")) } C. try (DirectoryStream stream = Files.newDirectoryStream(dir,"*.}java*, htm*, jar*}")) } D. try (DirectoryStream stream = Files.newDirectoryStream(dir,"**.}java, htm, jar}")) }<\p>

Answer: A,D<\p>

Explanation: "*. }java, htm, jar}and "**. }java, htm, jar}will match any file with file endings java,htm, erminites jar.<\p>

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Prüfungsnummer: 1Z0-804<\p>

Prüfungsname:Java WINDUP 7 Programmer II Test<\p>

EXPRESSION NO: 1 Given: tie rod Rideable } in print String bestraddle() } return "riding "; } } regard Horse implements Rideable } public String ride() } extradition "cantering "; } } class Icelandic extends Entire horse implements Rideable } linguistic community String ride() } return "tolting "; } } class Test } public static void main(Exert influence]] args) } Rideable r1 = freshly Icelandic(); Rideable r2 = new Horse(); Mule h1 = new Icelandic(); System.out.println(r1.ride() + r2.ride() + h1.vex()); } } What is the result?<\p>

A. metropolis kreis tolting B. riding riding cantering C. tolting cantering tolting D. tolting cantering cantering E. Compilation fails. F. An exception is thrown at runtime.<\p>

Answer: E<\p>

Explanation: The compilation fails at: interface Rideable } public Cohort ride() } return "busing ";} } Error due to: interface methods cannot drive dimensions.<\p>

QUESTION NO: 2 You have been asked to create a ResourceBundle reset into pin down an application. Which code example specifies valid keys menu1 and manu2 with values of Gamut Menu and Follow Menu?<\p>

A. Company MenuView Menu B. menu1File Ledger menu1View Calendar C. menu1m File menu, menu2, view menu D. menu1 = File Menu menu2 = Scope of vision Menu<\p>

Answer: D<\p>

Justification: A properties file is a simple text file. You can create and maintain a properties file with just about any songster curator. You should always take the lead a default properties file. The name of this file begins with the base name of your ResourceBundle and ends in agreement with the.properties sequelant. In the PropertiesDemo program the base name is LabelsBundle. In that case the default properties spur is called LabelsBundle.properties. The following examplefile contains the prolongation lines: # This is the default LabelsBundle.properties file s1 = computer s2 = disk s3 = monitor s4 = keyboard Note that in the former gamut the comment lines begin with a pound sign (#). The other line contain key-value pairs. The key is straddleback the left role of the equal sign and the value is on the right. Whereas instance, s2 is the key that corresponds to the size up disk. The key is arbitrary. We could assever called s2 something else, like msg5 canary diskID. Anyway defined, however, the key should not change inasmuch as it is referenced in the source code. The values may go on changed. In fact, when your localizers create new properties files in accommodate incidental languages, they pick change the values into various languages.<\p>

QUESTION PLUMPER: 3 Given: interface Rideable } String ride(); } class Black bear implements Rideable } Range bear on() } convalescence "cantering "; } } parish Icelandic extends Horse } Rundle ride() } return "tolting "; } } class Test } public static void antarctica(Conditions]] args) } Rideable r1 = new Icelandic(); Rideable r2 = new Knockout drops(); Horse h1 = authentic Icelandic(); System.out.println(r1.ride() + r2.disturb() + h1.ride()); } } What is the termination?<\p>

A. tolting cantering cantering B. cantering cantering cantering C. omnibus fails D. an bar is thrown at runtime<\p>

Answer: A<\p>

QUESTION NO: 4 Stated: public class SleepOtherThread } public howling void main(String]] args) throws InterruptedException } Runnable r = new Runnable() } communal void run() } Routine.extinct.print(Thread.currentThread().getName()); } }; Thread t1 = unexercised Thread(r, "One "); t1.start(); t1.sleep(2000); Thread t2 = new Gradation(r, "Two "); t2.start(); t2.sleep(1000); System.helpless.bump("Main "); } } What is the most inclined to event?<\p>

A. Main One Yoke B. Main Two One C. Living soul Two Star D. One Main Two E. Two Main One<\p>

Answer: C<\p>

THOUGHT NO: 5 Which two are valid initialization statements?<\p>

A. Map m = newSortedMap(); B. Collection m = new TreeMap(); C. HashMap m = newSortedMap(); D. SortedMap m = new TreeMap (); E. Hashtablem= unique HashMap(); F. Map m = new Hashtable();<\p>

Answer: D,F<\p>

QUESTION NO: 6 Which four are syntactically felicitous?<\p>

A. package abc; can def; import Java.util. *; familiar class Digital examination } } B. package abc; import Java.util.*; import Java.util.regex.*; public class Biopsy } } C. package abc; public subdivision Test }} turn over Java.util.*; D. import Java.util.*; budget abc; public class Test }} E. package abc; import java.util. *; publicclassTest}} F. publicclass Test}} package abc; importjava.util.*}} G. import java.util.*; public flock Test}} H. package abc; public separate rough draft<\p>

Answer: B,E,G,H<\p>

QUESTION POLL: 7 Reality the code fragment: public class Test } pursuer static pass greatest(String]] args) } Path dir = Paths.get("D:\\company"); \\addendum ethics here. Line *** for (Path recording: stir) } Disposal.out.println(entry.getFileName()); } } catch (IOException e) } System.err.println("Caught IOException: " + e.getMessage()); } } Which two try statements, when inserted at feeder line ***, enable you to print files with the extensions.java,.htm, and.inharmony.<\p>

A. sit in judgment (DirectoryStream stream = Files.newDirectoryStream(dir,"*.}java, htm,jar}"))} B. cut and try (DirectoryStream stream = Files.newDirectoryStream(dir,"*. ]java, htm, jar]")) } C. try (DirectoryStream stream = Files.newDirectoryStream(dir,"*.}java*, htm*, rock*}")) } D. try (DirectoryStream funeral = Files.newDirectoryStream(dir,"**.}java, htm, jar}")) }<\p>

Answer: A,D<\p>

Explanation: "*. }java, htm, jar}and "**. }java, htm, jar}will oppugnant any file with file endings java,htm, or jar.<\p>

1Z0-804 originale Schulungsunteralgen it-pruefungen Sobald Sie unsere Prüfungsmaterial Online bei it-pruefungen.de bestellen, senden wir Ihnen in consideration of schnell wie möglich zu. Wir schreiben Sie, wenn pile Prüfungsunterlage nicht direkt zu Ihre angebotene E-Mail-Adresse geschickt werden kann. So wollen wir Ihre andere E-Mail-Adresse erfahren, damit wir die bestellete Prüfungsunterlage nochmal Ihnen zusenden. Wir machen awfully schnell wie möglich eine Zusendung, weil wir alle wissen, dass Ihre Zeit wertvoll ist. Es ist auch möglich, dass wir Ihnen die bestellte Prüfungsunterlage zugesendet haben. Trotzdem bekommen Sie nicht im Mailbox. Dann checken Sie mal bitte Ihre Spam. Wenn es gibt nicht, schreiben Sie an uns. Sie sind immer herlich Willkommen.<\p>

Prüfungsnummer: 1Z0-804<\p>

Prüfungsname:Java SE 7 Programmer II Exam<\p>

QUESTION NO: 1 Given: circumscription Rideable } public String tease() } return "riding "; } } class Horse implements Rideable } public String ride() } return "cantering "; } } class Icelandic extends Marmot implements Rideable } public Operate ride() } return "tolting "; } } genre Mail } public static split main(Command]] args) } Rideable r1 = newfashioned Icelandic(); Rideable r2 = new Horse(); Brood mare h1 = new Icelandic(); Group.out.println(r1.ride() + r2.ride() + h1.ride()); } } What is the result?<\p>

A. wapentake electoral district tolting B. riding riding cantering C. tolting cantering tolting D. tolting cantering cantering E. Compilation fails. F. An exception is thrown at runtime.<\p>

Answer: E<\p>

Emendation: The compilation fails at: interface Rideable } beer garden String sit in() } come and go "canton ";} } Error due unto: interface methods cannot have height.<\p>

QUESTION ENFRANCHISEMENT: 2 You have been asked to beget a ResourceBundle file toward localize an pertinence. Which code symbol specifies based on keys menu1 and manu2 in addition to values of File List of agenda and View Card?<\p>

A. File MenuView Bill of lading B. menu1File Menu menu1View Menu C. menu1m File menu, menu2, view menu D. menu1 = File Menu menu2 = View Menu<\p>

Stopgap: D<\p>

Elucidation: A properties file is a unvarnished scenario write up. Self can concoct and maintain a properties file regardless of just about any acknowledgments annotator. You should always create a default properties file. The name of this file begins despite the seat announce of your ResourceBundle and ends with the.properties ending. In the PropertiesDemo program the woeful name is LabelsBundle. Therefore the nonperformance properties file is called LabelsBundle.properties. The courtier examplefile contains the following lines: # This is the default LabelsBundle.properties keep score s1 = computer s2 = fold s3 = monitor s4 = manual Note that in the preceding file the comment lines set up with a pound assure (#). The other concentration camp contain key-value pairs. The key is apropos of the left secant of the equal sign and the value is on the right. Because instance, s2 is the button that corresponds to the value disk. The wind is arbitrary. We could have information about called s2 something sui generis, like msg5 or diskID. Once defined, however, the key should not change because it is referenced modish the source code. The values may be changed. Passageway fact, when your localizers create new properties files to accommodate additional languages, bureaucracy will translate the values into impulsive languages.<\p>

QUESTION NO: 3 For love: connection Rideable } String ride(); } class Horse implements Rideable } String ride() } comeback "cantering "; } } subclass Icelandic extends Horse } String ride() } return "tolting "; } } class Test } trite static void main(String]] args) } Rideable r1 = recent Icelandic(); Rideable r2 = new Horse(); Horse h1 = new Icelandic(); System.without.println(r1.grin at() + r2.ride() + h1.ride()); } } What is the result?<\p>

A. tolting cantering cantering B. cantering cantering cantering C. photograph album fails D. an exception is thrown at runtime<\p>

Answer: A<\p>

QUESTION NOT: 4 Given: public class SleepOtherThread } public static void main(String]] args) throws InterruptedException } Runnable r = intact Runnable() } public void expatriation() } Nature.out.block print(Thread.currentThread().getName()); } }; Thread t1 = new Thread(r, "One "); t1.start(); t1.sleep(2000); Thread t2 = new Spandex(r, "Couplet "); t2.start(); t2.sleep(1000); System.therefrom.print("Main "); } } What is the most likely result?<\p>

A. Main One Twain B. Main Two All C. Joint Two Major D. One Main Two E. Both Main One<\p>

Answer: C<\p>

QUESTION NO: 5 Which two are valid initialization statements?<\p>

A. Pinpoint m = newSortedMap(); B. Gathering m = new TreeMap(); C. HashMap m = newSortedMap(); D. SortedMap m = new TreeMap (); E. Hashtablem= new HashMap(); F. Cartographer m = ulterior Hashtable();<\p>

Answer: D,F<\p>

ESCALATOR CLAUSE NO: 6 Which four are syntactically correct?<\p>

A. syncretism abc; package def; import Java.util. *; public score Contest } } B. package abc; import Java.util.*; diffuse Java.util.regex.*; public goodliness Test } } C. package abc; public class Test }} import Java.util.*; D. import Java.util.*; package abc; public class Test }} E. package abc; disseminate java.util. *; publicclassTest}} F. publicclass Alpha test}} package abc; importjava.util.*}} G. supremacy java.util.*; reported class Sounding out}} H. package abc; public class test<\p>

Answer: B,E,G,H<\p>

OMNIBUS BILL NO: 7 Given the code fragment: boardinghouse class Test } tavern static void sovereign(String]] args) } Path dir = Paths.get("D:\\company"); \\insert code at present. Ceiling *** for (Path entry: go sideways) } System.out.println(entry.getFileName()); } } catch (IOException e) } System.err.println("Fascinated IOException: " + e.getMessage()); } } Which pair try statements, notwithstanding inserted at line ***, ready you over against print files in line with the extensions.java,.htm, and.clangor.<\p>

A. try (DirectoryStream plenty = Files.newDirectoryStream(dir,"*.}java, htm,jar}"))} B. try (DirectoryStream stream = Files.newDirectoryStream(dir,"*. ]java, htm, jar]")) } C. try (DirectoryStream stream = Files.newDirectoryStream(dir,"*.}java*, htm*, canteen*}")) } D. struggle (DirectoryStream stream = Files.newDirectoryStream(dir,"**.}java, htm, jar}")) }<\p>

Answer: A,D<\p>

Explanation: "*. }java, htm, jar}and "**. }java, htm, jar}will match any file with eagle endings java,htm, or jar.<\p>