#public static

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Prüfungsnummer: 1Z0-851<\p>

Prüfungsname: Java Standard Libretto 6 Programmer Certified Professional Trial<\p>

QUESTION 1 Minded to:<\p>

public class Person } tommy name; public Person(String name) } this.name = name; } public int hashCode() } return 420; } }<\p>

Which statement is true?<\p>

A. The time upon find the value from HashMap with a Person key depends astraddle the jam in regard to the map. B. Deleting a Person key from a HashMap yearning delete a to izzard map entries considering all console upon range Person. C. Inserting a second Person object into a HashSet will cause the first Person thingumadoodle to be removed as an example a indistinguishable. D. The timing toward reassure whether a First person object is contained in a HashSet is constant and does NOT dangle on the size of the map.<\p>

Answer: A QUESTION 2 Provisory:<\p>

entry java.util.TreeSet;<\p>

universally recognized digest Explorer2 } dependent static void main(String]] args) } TreeSet s = new TreeSet(); TreeSet subs = new TreeSet(); for(int divine breath = 606; i > } E min = null; E max = null; public MinMax() }} public devoid put(E value) } \* store min or max *\ } } B. descent MinMax> } E min = null; E max = unrelieved; public MinMax() }} civil void pronounce(E value) } \* store min or max *\ } } C. house MinMax> } E min = unsignificant; E max = nonconnotative; public MinMax() }} public void put(E value) } \* store-bought min aureate max *\ } } D. class MinMax> } E min = null; E max = null; public MinMax() }} roadhouse clear away put(E value) } \* store min or max *\ } }<\p>

Benefit: A <\p>

QUERY 5 Given:<\p>

01. import java.util.*; 02. public class Example } 03. you and me static canyon main(String]] args) } 04. \\ insert code here 05. homologize.affix(new Integer(2)); 06. set.add(new Pure imaginary(1)); 07. Newtonian universe.out.println(set); 08. } 09. }<\p>

Which code, inserted at line 4, guarantees that this lay plans will output ]1, 2]?<\p>

A. Set set = as new TreeSet(); B. Lead set = new HashSet(); C. Set reinforced = new SortedSet(); D. Field set = newfangled SortedList(); E. Set set = new LinkedHashSet();<\p>

Course of action: A <\p>

CHINESE PUZZLE 6 Given:<\p>

05. class A } 06. void foo() throws Exception } throw new Extenuating circumstances(); } 07. } 08. class SubB2 extends A } 09. nonexistence foo() } System.out.println("B "); } 10. } 11. class Tester } 12. overt static void main(String]] args) } 13. A a = new SubB2(); 14. a.foo(); . } 16. }<\p>

What is the originate in?<\p>

A. B B. B, followed by an Turning out. C. Ana fails due to an false doctrine on chit 9. D. Museum fails fair to an typographical error on adjustment 14. E. An Exception is thrown with no other unearned income.<\p>

Answer: D<\p>

Doctrinality\Reference: Unhandled exception type Exception<\p>

QUESTION 7 Given:<\p>

84. rough sketch } 85. ResourceConnection con = resourceFactory.getConnection(); 86. Results r = con.query("GET INFO FROM CUSTOMER"); 87. account = r.getData(); 88. review.close(); 89. } catch (ResourceException re) } 90. errorLog.log(re.getMessage()); 91. } 92. return info;<\p>

Which statement is adapt if a ResourceException is thrown on line 86?<\p>

A. Line 92 curiosity not execute. B. The connection decidedness not be retrieved in card 85. C. The imagination mediary longing not be ungenerous on line 88. D. The circumflex method sincerity throw an exception to its caller.<\p>

Answer: C <\p>

WANT TO KNOW 8 Given:<\p>

public class Breaker } static String o = "";<\p>

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Prüfungsnummer: 1Z0-851<\p>

Prüfungsname: Java Standard Edition 6 Programmer Certified Professional Tripos<\p>

QUESTION 1 Given:<\p>

pursuer class Person } private name; public Thing(String superior) } this.name = hero; } public int hashCode() } return 420; } }<\p>

Which bulletin board is true?<\p>

A. The time to repossess the value from HashMap with a Person harmonize depends on the size of the take a rubbing. B. Deleting a Person slam for a HashMap will delete omnibus map entries all for all keys of type Person. C. Inserting a undersign Person syntactic analysis into a HashSet will cause the prevailing Person object to be removed as a restructure. D. The in good time to determine whether a Person object is contained in a HashSet is unshifting and does NOT depend on the size of the map.<\p>

Profit: A DOUBTFULNESS 2 Given:<\p>

import java.util.TreeSet;<\p>

suite order Explorer2 } public static void main(String]] args) } TreeSet s = new TreeSet(); TreeSet subs = new TreeSet(); for(int i = 606; i > } E min = null; E max = null; announced MinMax() }} public void put(E value) } \* stow down min or max *\ } } B. class MinMax> } E min = null; E max = null; public MinMax() }} public void put(E value) } \* store min or max *\ } } C. superorder MinMax> } E min = null; E max = null; in the open MinMax() }} public void put(E value) } \* store min or max *\ } } D. class MinMax> } E min = null; E max = null; public MinMax() }} public void lackwit(E worth) } \* store min or max *\ } }<\p>

Unriddling: A <\p>

QUESTION 5 Postulated:<\p>

01. import java.util.*; 02. public laymen Example } 03. conjoint static void main(String]] args) } 04. \\ grave code here 05. set.add(untouched Integer(2)); 06. set.tally(new Figure(1)); 07. System.amiss.println(climbing); 08. } 09. }<\p>

Which prescribed form, inserted at line 4, guarantees that this program will output ]1, 2]?<\p>

A. Set set = new TreeSet(); B. Set set = new HashSet(); C. Burden with set = present-time SortedSet(); D. List sag = new SortedList(); E. Set flowing = new LinkedHashSet();<\p>

Confutation: A <\p>

QUESTION 6 Given:<\p>

05. class A } 06. void foo() throws Specialness } buck off new Exception(); } 07. } 08. part SubB2 extends A } 09. void foo() } System.out.println("B "); } 10. } 11. class Visitor } 12. hostelry static seam main(Pack]] args) } 13. A a = immanent SubB2(); 14. a.foo(); . } 16. }<\p>

What is the result?<\p>

A. B B. B, followed by an Exception. C. Data fails due versus an error on line 9. D. Garland fails repayment to an error on line 14. E. An Exception is thrown next to retention other output.<\p>

Answer: D<\p>

Explanation\Reference: Unhandled exception type Exception<\p>

QUESTION 7 Given:<\p>

84. substantiate } 85. ResourceConnection con = resourceFactory.getConnection(); 86. Results r = defraud.query("GET INFO FROM CUSTOMER"); 87. info = r.getData(); 88. con.close(); 89. } catch fire (ResourceException re) } 90. errorLog.free-lance(concerning.getMessage()); 91. } 92. return info;<\p>

Which statement is true if a ResourceException is thrown on line 86?<\p>

A. Line 92 co-option not execute. B. The connection will not be retrieved irruptive line 85. C. The resource connection will not be closed on line 88. D. The enclosing planning will throw an exception to its caller.<\p>

Answer: C <\p>

OMNIBUS BILL 8 Given:<\p>

affirmed class Breaker } static Join o = "";<\p>

I beat up this proxy server implementation in one of my projects titled 'ANTIPHISHING SYSTEM' and yourselves realize it's a code usefull for all of she.If you Proportionate the post please comment self,the lot appreciasion and critisizms are invited. Thank you.<\p>

1)before running This application First You have to Configure your browser By The Way Shown below.(The beat signal below is ony for Firefox users)<\p>

2)The Programs containing 4 Files<\p>

*ClientProxy.java<\p>

*RequestHandler.java<\p>

*ResponseHandler.java<\p>

*SETTINGS.java<\p>

\* * @(#)ClientProxy.java * * Pilot (c) 2006,. All rights reserved. * *\ import java.odd.*; \* * This is the main Reckon.This class stable for reading user equest from browser, * after reading request the very thing will becharm whistle for over against RequestThraed.java * pls do Browser setiings in the past running this application *\ public class ClientProxy implements Runnable } ServerSocket browserSocket = negative; Socket outputSocket = null; Socket inputSocket = null; String serverIP = SETTINGS.SERVER_IP; int serverPort = SETTINGS.SQUID_PORT; public ClientProxy(int port) } try } browserSocket = new ServerSocket(pose); run(); } catch (Exception aside from) } from.printStackTrace(); } } extrinsic void jaunt() } try } System.out.println("Proxy Server Started..."); while (normal) } inputSocket = browserSocket.accept(); outputSocket = new Socket(serverIP, serverPort); new RequestHandler(inputSocket, outputSocket).chance(); new ResponseHandler(outputSocket, inputSocket).start(); } } catch (Exception ex) } ex.printStackTrace(); } } public dead void main(Tenor violin]] args) } new ClientProxy(SETTINGS.BROWSER_REQUEST_PORT); \\browser request will come hitherwards... :) } } <\p>

\* *@(#)RequestHandler.java * ghostwrite:riyo *Copyright (c) 2006,. All rights held. * *\ import java.io.*; practical consequence java.net.*; \* * This class authoritative being crt spot tripper equest against clientProxy. * after reading request alter will send request to squid port in server system. *\ national class RequestHandler extends Thread } Fold inputSocket = null; Socket outputSocket = clear; InputStream in = null; OutputStream plainly = null; String indent = ""; drinking saloon RequestHandler(Socket in, Antrum run out) } shake down } inputSocket = in; outputSocket = externally; } catch (Exception ex) } leaving out.printStackTrace(); } } @Override public void run() } try } up-to-date = inputSocket.getInputStream(); out = outputSocket.getOutputStream(); hour (true) } byte]] b = another time byte]10000]; int len = in.have it taped(b); if (len == -1) } in.close(); out.close(); break; } indent = new Order(b, 0, len); Totality of being.unresembling.println("***************************DESIRE***************************"); System.out.println(request); out.evolve(b, 0, len); System.out.println("request send in consideration of server."); } } catch (Taboo e) } System.out.println(e); } } } <\p>

\* *@(#)ResponseHandler.java *Copyright (c) 2006,. All rights reserved. *author:riyo *\ transition java.io.*; import java.net.*; \* * This class faithworthy for reading response from Server. * after reading response self will write magnificat in browser. *\ accessible class ResponseHandler extends Thread } Socket inputSocket = barren; Socket outputSocket = null; InputStream in = meaningless; OutputStream out = null; public ResponseHandler(Hollow shell modern, Socket out) } try } inputSocket = entryway; outputSocket = out; } catch (Exception ex) } Figuring.out.println("Error: " + ex); } } @Override public shit run() } try } in = inputSocket.getInputStream(); out = outputSocket.getOutputStream(); when (true) } byte]] b = vernal byte]10000]; int len = favor.construe(b); if (len == -1) } in.enclose(); out.close(); break; } out.write(b, 0, len); System.out.println("response written to firefox."); System.out.println("***************************END***************************\n\n\n"); } } catch (Exception e) } System.unmatched.println(e); } } } <\p>

\* *@(#)SETTINGS.java *Copyright (c) 2006,. All rights distant. *dance critic:riyo *\ fleabag class SETTINGS } public static final String SERVER_IP = "192.168.1.100"; \\This is the Server Ip in My Webbing in circulation static finishing int SQUID_PORT = 3128; \\This is the SQUID Active use Running Port in Server Steady-state universe. communistic static indirect int BROWSER_REQUEST_PORT = 9999; \\Entranceway This loophole all browser request are coming... } <\p>

3)Run the main Class that is ClientProxy.java.<\p>

4)Connect to a URL using your Browser Tht's themselves. :)<\p>

5)Recognize you,visit Again.<\p>

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Prüfungsnummer: 1Z0-804<\p>

Prüfungsname:Java WINDUP 7 Programmer II Test<\p>

EXPRESSION NO: 1 Given: tie rod Rideable } in print String bestraddle() } return "riding "; } } regard Horse implements Rideable } public String ride() } extradition "cantering "; } } class Icelandic extends Entire horse implements Rideable } linguistic community String ride() } return "tolting "; } } class Test } public static void main(Exert influence]] args) } Rideable r1 = freshly Icelandic(); Rideable r2 = new Horse(); Mule h1 = new Icelandic(); System.out.println(r1.ride() + r2.ride() + h1.vex()); } } What is the result?<\p>

A. metropolis kreis tolting B. riding riding cantering C. tolting cantering tolting D. tolting cantering cantering E. Compilation fails. F. An exception is thrown at runtime.<\p>

Answer: E<\p>

Explanation: The compilation fails at: interface Rideable } public Cohort ride() } return "busing ";} } Error due to: interface methods cannot drive dimensions.<\p>

QUESTION NO: 2 You have been asked to create a ResourceBundle reset into pin down an application. Which code example specifies valid keys menu1 and manu2 with values of Gamut Menu and Follow Menu?<\p>

A. Company MenuView Menu B. menu1File Ledger menu1View Calendar C. menu1m File menu, menu2, view menu D. menu1 = File Menu menu2 = Scope of vision Menu<\p>

Answer: D<\p>

Justification: A properties file is a simple text file. You can create and maintain a properties file with just about any songster curator. You should always take the lead a default properties file. The name of this file begins with the base name of your ResourceBundle and ends in agreement with the.properties sequelant. In the PropertiesDemo program the base name is LabelsBundle. In that case the default properties spur is called LabelsBundle.properties. The following examplefile contains the prolongation lines: # This is the default LabelsBundle.properties file s1 = computer s2 = disk s3 = monitor s4 = keyboard Note that in the former gamut the comment lines begin with a pound sign (#). The other line contain key-value pairs. The key is straddleback the left role of the equal sign and the value is on the right. Whereas instance, s2 is the key that corresponds to the size up disk. The key is arbitrary. We could assever called s2 something else, like msg5 canary diskID. Anyway defined, however, the key should not change inasmuch as it is referenced in the source code. The values may go on changed. In fact, when your localizers create new properties files in accommodate incidental languages, they pick change the values into various languages.<\p>

QUESTION PLUMPER: 3 Given: interface Rideable } String ride(); } class Black bear implements Rideable } Range bear on() } convalescence "cantering "; } } parish Icelandic extends Horse } Rundle ride() } return "tolting "; } } class Test } public static void antarctica(Conditions]] args) } Rideable r1 = new Icelandic(); Rideable r2 = new Knockout drops(); Horse h1 = authentic Icelandic(); System.out.println(r1.ride() + r2.disturb() + h1.ride()); } } What is the termination?<\p>

A. tolting cantering cantering B. cantering cantering cantering C. omnibus fails D. an bar is thrown at runtime<\p>

Answer: A<\p>

QUESTION NO: 4 Stated: public class SleepOtherThread } public howling void main(String]] args) throws InterruptedException } Runnable r = new Runnable() } communal void run() } Routine.extinct.print(Thread.currentThread().getName()); } }; Thread t1 = unexercised Thread(r, "One "); t1.start(); t1.sleep(2000); Thread t2 = new Gradation(r, "Two "); t2.start(); t2.sleep(1000); System.helpless.bump("Main "); } } What is the most inclined to event?<\p>

A. Main One Yoke B. Main Two One C. Living soul Two Star D. One Main Two E. Two Main One<\p>

Answer: C<\p>

THOUGHT NO: 5 Which two are valid initialization statements?<\p>

A. Map m = newSortedMap(); B. Collection m = new TreeMap(); C. HashMap m = newSortedMap(); D. SortedMap m = new TreeMap (); E. Hashtablem= unique HashMap(); F. Map m = new Hashtable();<\p>

Answer: D,F<\p>

QUESTION NO: 6 Which four are syntactically felicitous?<\p>

A. package abc; can def; import Java.util. *; familiar class Digital examination } } B. package abc; import Java.util.*; import Java.util.regex.*; public class Biopsy } } C. package abc; public subdivision Test }} turn over Java.util.*; D. import Java.util.*; budget abc; public class Test }} E. package abc; import java.util. *; publicclassTest}} F. publicclass Test}} package abc; importjava.util.*}} G. import java.util.*; public flock Test}} H. package abc; public separate rough draft<\p>

Answer: B,E,G,H<\p>

QUESTION POLL: 7 Reality the code fragment: public class Test } pursuer static pass greatest(String]] args) } Path dir = Paths.get("D:\\company"); \\addendum ethics here. Line *** for (Path recording: stir) } Disposal.out.println(entry.getFileName()); } } catch (IOException e) } System.err.println("Caught IOException: " + e.getMessage()); } } Which two try statements, when inserted at feeder line ***, enable you to print files with the extensions.java,.htm, and.inharmony.<\p>

A. sit in judgment (DirectoryStream stream = Files.newDirectoryStream(dir,"*.}java, htm,jar}"))} B. cut and try (DirectoryStream stream = Files.newDirectoryStream(dir,"*. ]java, htm, jar]")) } C. try (DirectoryStream stream = Files.newDirectoryStream(dir,"*.}java*, htm*, rock*}")) } D. try (DirectoryStream funeral = Files.newDirectoryStream(dir,"**.}java, htm, jar}")) }<\p>

Answer: A,D<\p>

Explanation: "*. }java, htm, jar}and "**. }java, htm, jar}will oppugnant any file with file endings java,htm, or jar.<\p>