#neverendings

Sofia smirked a little "Of course I have been staring." She said. "Should I not stare at you? I promise, its merely because I like what I see." She told him. "Nothing bad, I promise." She chuckled a little "Just admiring the view."

"Am I not allowed to do that?" She asked curiously, a little smirk still on her lips.

"Maxwell, I am not asking you to fix anything." Sofia said, looking at him. She took a breath, trying to keep her calm. "Max, I have no Pack left, I am asking you to please be with me while I do a ritual that was part of my Packs belief. You do not have to do anything, except be there with me." She told him. "Please, I just... don't want to be alone." She told him. She had done so many of them alone, and it was emotionally draining. "I just want you there, you don't have to do anything, or fix anything, just... please?" She asked him, her hand reaching for his. "You know I am here now, but they were my family, and I want to continue to remember them, and honour them."

— life-is-average

Noo problem!

This question is largely conceptual.

First of all, we want to get the speed in mi/hr of the boat when traveling towards or against the current. 

Towards: 24 mi/3 hr = 8 mi/hr Against: 16 mi/4 hr = 4 mi/hr

Now, we know that the velocity of the boat with the current would be:

Vboat + Vcurrent = Vwithcurrent

Similarly, the velocity of the boat against the current would be:

Vboat - Vcurrent = Vnotcurrent

Thus, we can set up the system of equations by replacing those variables with our known velocities.

Vboat + Vcurrent = Vwithcurrent --> Vboat + Vcurrent = 8 mi/hr Vboat - Vcurrent = Vnotcurrent --> Vboat - Vcurrent = 4 mi/hr

So, you can add those two equations together like this:

    Vboat + Vcurrent = 8 mi/hr +) Vboat - Vcurrent = 4 mi/hr --------------------------------- 2Vboat = 12 mi/hr

Thus, Vboat = 6 mi/hr

Then, Vboat + Vcurrent = 8 mi/hr --> 6 mi/hr + Vcurrent = 8 mi/hr

So Vcurrent = 2 mi/hr! :)

Welp, I just posted an answer on how to combine variable terms, so if you wouldn't mind scrolling down a post or two to see that really long, detailed explanation, that would be great! 

The steps:

1. Original: 3x2y-2y-(3/2)x-3x-2y2y-7

2. Add/subtract like variables: 3x2y - 2y - (9/2)x - 2y2y - 7

3. Combine variables that are the same: 3x2y - 2y - (9/2)x - 4y^2 - 7

Well basically, you want to start out at the beginning with the number you're being asked to convert. For instance, here's a problem:

Convert 345 centimeters to miles with the conversion factors 100 cm = 1 m, 1 m = 3.28 ft, 5280 ft = 1 mi

The problem is asking you to convert 345 centimeters, so that's what you start out with. Then, you should look for a conversion factor (it may not be given for you, like I did here, but there will be a conversion factor out there for your problem, I promise! :]) that includes a value with the same unit. Since 345 is in CENTIMETERS, or cm, the next conversion factor/proportion you would use is 100 cm = 1 m. Now your conversion looks like this

345 cm x (1 m/100 cm)

The reason you multiply by one thing divided by another is because 1m/100 cm is equal to one, since 1 m and 100 cm are, as stated above, equal and the same thing. The thing with dimensional analysis is that you want to convert units, not change the original value. That is why every time you use a conversion factor, it must divide out to become 1. The 100 cm is on the bottom is because you can only cancel out units if one is on top and one is on bottom. Now, after you cancel out the cm, you are left with the unit METERS, or m, on top. Now, you repeat the process - look for a proportion given that has meters as the unit. In this case, you would be using 1 m = 3.28 ft. Now your equation would look like this:

345 cm x (1 m/100 cm) x (3.28 ft/1 m)

Continuing on...your overall equation should look something like this: