#maths solutions

Exercise : 1.1

Question 1. Use Euclid's division algorithm to find HCF of

(i) 135 and 225

(ii) 196 and 38220

(iii) 867 and 255

Solution 1.

(i) 135 and 225

Since 225>135, we can apply Euclid's division lemma to 225 and 135

225 = 135×1 + 90

Since the remainder 90≠0 , we can apply Euclid's division lemma to 135 and 90

135 = 90×1 + 45

Again we can see that the remainder 45≠0 we will again apply Euclid's division lemma to 90 and 45

90 = 45×2 + 0

We get remainder = 0

So in last step divisor is 45 so the HCF of 135 and 225 is 45.

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Bihar Board Class 10 Maths Solutions Chapter 1

Hello Students and Teachers. Are you searching for the Solutions of Bihar Board Class 10 Maths Chapter 1? If yes then you have come to the right place. On this page, we have presented you with the Solutions of Chapter 1: वास्तविक संख्याएँ. These solutions have been prepared by experts and are designed to help students understand the concepts and solve the problems in an easy and effective way.

नमस्कार छात्रों और शिक्षकों। क्या आप बिहार बोर्ड कक्षा 10 गणित अध्याय 1 का हल खोज रहे हैं? अगर हां तो आप सही जगह पर आए हैं। इस पृष्ठ पर, हमने आपको अध्याय 1: वास्तविक संख्याएँ के समाधान प्रस्तुत किए हैं। ये समाधान विशेषज्ञों द्वारा तैयार किए गए हैं और छात्रों को अवधारणाओं को समझने और समस्याओं को आसान और प्रभावी तरीके से हल करने में मदद करने के लिए डिज़ाइन किए गए हैं।