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In python, how can I print lines that do NOT contain a certain string, rather than print lines which DO contain a certain string:
Youre asking whether the expression (StatusRequest or StatusResponse) appears in line. But that expression is just the same thing as StatusRequest.
Put it in English: youre not trying to say if neither of these is in line. Python doesnt have a neither/none function, but it does have an any function, so you can do this:
In python, how can I print lines that do NOT contain a certain string, rather than print lines which DO contain a certain string:
Youre asking whether the expression (StatusRequest or StatusResponse) appears in line. But that expression is just the same thing as StatusRequest.
Put it in English: youre not trying to say if neither of these is in line. Python doesnt have a neither/none function, but it does have an any function, so you can do this:
Best way to handle list.index(might-not-exist) in python?
Best way to handle list.index(might-not-exist) in python?
I have code which looks something like this:
thing_index = thing_list.index(thing) otherfunction(thing_list, thing_index)
ok so thatâs simplified but you get the idea. Now thing might not actually be in the list, in which case I want to pass -1 as thing_index. In other languages this is what youâd expect index() to return if it couldnât find the element. In fact it throws a ValueError.
I couldâŚ
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Divide a list into 3 parts in python [duplicate]
Divide a list into 3 parts in python [duplicate]
This question already has an answer here:
splitting a list of arbitrary size into only roughly N-equal parts 10 answers
I am looking to divide a list into 3 parts in python. If the list doesnât divide by 3, I would like it to âfillâ the first column then the second, then the third.
e.g:
1|2|3 1|3| 2| 1|3| 2|4| 1|3|5 2|4| 1|3|5 2|4|6
And so on.
I amâŚ
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Discovering a class's metaclass in Python 3
Discovering a classâs metaclass in Python 3
In Python 2, I could check a classâs __metaclass__ attribute to discover its metaclass. How do I the same thing in Python 3?
Best Answer
Use the single-argument type function (type(class)), or just access class.__class__. Both of these work in Python 2, btw.
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Basics of Object Oriented Programming in Python
Basics of Object Oriented Programming in Python
Object Oriented Programming in Python Object
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