Code Panda

Sometimes you need to use an updated version of python on your project, in this case you need install python 3, but you already stuck with yum because there is no option to install it officially from epel-release.

And GOOD NEWS, now centos7 with the repo EPEL7 finally has python 3.4!!, yeah that really-really awesome!

So that simply for you to use it, just run some steps below will make you happy and save your day

sudo yum install epel-release sudo yum install python34

To check if you successfully installed for python 3, simply check by running code below

[aditya@pasarpanda development]$ python3.4 Python 3.4.3 (default, Jun 19 2015, 05:46:30) [GCC 4.8.3 20140911 (Red Hat 4.8.3-9)] on linux Type "help", "copyright", "credits" or "license" for more information. >>> exit()

Then here is, how to install pip by using python34 that we just installed before

wget https://bootstrap.pypa.io/get-pip.py python3.4 get-pip.py

Cool, you just installed pip with python3

Test your pip by executing this command pip -V

If you need to create a new virtualenv with this python3.4, you can create a new one with -p option when you create it

Do you have any experience with manipulating list of python when you need to remove one or multiple values inside of it, imagine we have a list like this:

fruits = [’banana’, ‘orange’, ‘watermelon’, ‘apple’]

Then you need to remove value based on it's index like “banana” and “apple” inside “fruits” list, how to make them work ? looping over the list values and delete them by an index number ?

Here what can we get, about delete those by loop

fruits = [’banana’, ‘orange’, ‘watermelon’, ‘apple’] index_to_delete = [0, 3] for idx, fruit in enumerate(fruits): if idx in index_to_delete: del fruits[idx] # This just works on first deletion

As you can see above, you code will breaks after you do delete on second time on loop, because the index you’re going to remove is changed as time as the loop process running. So what can we do about those ?

Because the index of those list will be change every time we remove the value, we can do this by populate a new list values without deleted values inside of it.

fruits = [’banana’, ‘orange’, ‘watermelon’, ‘apple’] index_to_delete = [0, 3] fruits = [fruit for idx, fruit in enumerate(fruits) if idx not in index_to_delete] # Here what you will get fruits = [’orange’, ‘watermelon’]

Perhaps in some times you need to grab some value directly from url when using javascript language This is what you need to do based on this stackoverflow page

function getUrlVars(){ var vars = [], hash; var hashes = window.location.href.slice(window.location.href.indexOf('?') + 1).split('&'); for(var i = 0; i < hashes.length; i++) { hash = hashes[i].split('='); vars.push(hash[0]); vars[hash[0]] = hash[1]; } return vars; }

For example if you using url like this

http://www.example.com/?me=myValue&name2=SomeOtherValue

You will be able to grab these parameter using returned value like this