#stackoverflowerror

Memory Model of Java Virtual Machine

The Java Virtual Machine is an abstract computing machine. It is responsible for most of the features which made Java a great technology. Few of the major selling points of Java was:

Platform Independence

Hardware Independence

Operating System Independence

Security from malicious programs

It is said to be abstract computing machine because it offers all the specification which if implemented…

How to: Why does this method print 4?

Why does this method print 4?

I was wondering what happens when you try to catch an StackOverflowError and came up with the following method:

class RandomNumberGenerator { static int cnt = 0; public static void main(String[] args) { try { main(args); } catch (StackOverflowError ignore) { System.out.println(cnt++); } } }

Now my question:

Why does this method print ‘4’?

I thought maybe it was…

try-finally block prevents StackOverflowError

Take a look at the following two methods:

public static void foo() { try { foo(); } finally { foo(); } } public static void bar() { bar(); }

Running bar() clearly results in a StackOverflowError, but running foo() does not (the program just seems to run indefinitely). Why is that?

Answer: try-finally block prevents StackOverflowError

When you get an…