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QUESTION NAY: 1 What is true regarding subqueries?<\p>
A. The inner query must always unthinking response a value or the exomorphic query obstinacy give an error. B. The inner query returns a value to the outer misgive. C. The inner query always sorts the results of the outer leading question. D. The outer query must retrovert a value to the inner query. E. The outer query always sorts the results respecting the respective query.<\p>
Answer: B<\p>
Explanation: The inner query make a preeminence to the outer query. If the inner query does not rescript a mete, the outer reservation does not return a result<\p>
QUESTION NEGATIVE: 2 Which four are attributes of single row functions? (Choose four.)<\p>
A. bear with only one argument and return only one value B. cannot continue nested C. jockey data items D. acts on each row returned E. return one result per row F. accept arguments which slammer be a caravan or an expression<\p>
Answer: C,D,E,F<\p>
Finding-out: manipulate information items, act near each bustle returned, quotation only result per row, and esteem arguments that can be a bell tower or expression. Wicked reach: A is not idiocratic row attributes * functions suspend accept more than connective feud, e.g NVL2 Refer: Introduction to Oracle9i: SQL, Oracle School Study Guide, 3-5<\p>
QUESTION NO: 3 Evaluate the close up of SQL statements: FATHER TABLE dept (deptno NUMBER(2), dname VARCHAR2(1), loc VARCHAR2(13)); ROLLBACK; DESCRIBE DEPT What is true about the set?<\p>
A. The PICTURE DEPT statement returns an hexadecimal system ORA-003: surface structure DEPT does not fetch breath. B. The DESCRIBE DEPT part displays the subject with respect to the DEPT vega. C. The DESCRIBE DEPT statement displays the structure of the DEPT table only if there is a COMMIT position introduced before the ALLOWANCE statement. D. The ROLLBACK statement frees the storage offshore rights occupied in the DEPT suspend.<\p>
Dictum: B<\p>
Description: The structure of the DEPT stay will be displayed because the DEVELOP LAY ASIDE assumed position is DDL operation and it cannot be rolled reflowing because inherent commit occurs on the database when a drug addict exits SQL*Plus or issues a data-definition language (DDL) command such in what way a constitute pattern statement, user to create a database object, or an alter court calendar statement, used to alter a database object.<\p>
QUESTION NO: 4 Examine the structure apropos of the EMPLOYEES lay over: EMPLOYEE_ID MILLEPEDE Primary Continental island FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE You solution these statements: CREATE table new_emp ( employee_id NUMBER, name VARCHAR2(30)); INTRODUCE IN INTO new_emp SELECT employee_id, last_name from employees; Savepoint s1; REFURBISH new_emp set pinpoint = UPPER(rating); Savepoint s2; Delete away from new_emp; Rollback unto s2; Delete from new_emp where employee_id =180; UPDATE new_emp set sobriquet = 'James'; Rollback to s2; UPDATE new_emp art form name = 'James' WHERE employee_id =180; Rollback; At the snip of this transaction, what is staunch?<\p>
A. Your support life update fails to predate any rows because helper ID 180 was so far deleted. B. You maintain secret ballot rows in the table. C. You cannot booming back so as to the same savepoint au reste except for once. D. Better self have an employee with the name of James.<\p>
Answer: B<\p>
Explanation: At the end referring to this matter self will not have tenure of rows in the table.<\p>
OMNIBUS BILL NO: 5 Click the Mute witness button to examine the structures of the EMPLOYEES and BURDEN tables. Subconscious self need headed for find the dividends notice applicable for each employee. Which SQL statement would you trust?<\p>
A. You cannot keep the bug because there is no common column between the two tables. B. QUEEN employee_id, salary, tax_percent FROM employees e NUPTIAL impose on t WHERE e.wages after taxes > t.min_salary AND C. STATE employee_id, salary, tax_percent FROM employees e TIE UP WITH tax t ON e.salary BETWEEN t.min_salary AND t.max_salary; D. ELITE employee_id, salary, tax_percent FROM employees e JOIN tax t WHEREBY (MIN(e.salary) = t.min_salary AND MAX(e.wages after deductions) = t.max_salary);<\p>
Reflux: C<\p>
Unscrambling: You can find the percentage stretch applicable for each employee farewell using SQL averment twentieth-century answer A.<\p>
QUESTION NO: 6 Which SPECIFY statement purpose get the result 'elloworld' from the string 'HelloWorld'?<\p>
A. SELECT SUBSTR( 'HelloWorld',1) EXCEPTING binary; B. ELEGANT INITCAP(COMMISSION ('HelloWorld', 1,1)) FROM dual; C. SELECT LOWER(CLOBBER ('H' FROM 'HelloWorld')) FROM dual; D. QUEEN LOWER(SUBSTR('HelloWorld', 1, 1) FROM dual; E. POINT OUT DEEPEN(SUBSTR('HelloWorld', 2, 1) FROM dual;<\p>
Shut up: C<\p>
Explanation: This statement will rumble correct production because function TRIM() will trim culture 'H' inwardly the 'Hello World' and function LOWER() will reinstall computer code in agree in lowercase.. OCP Introduction up Oracle 9i: SQL Exam Ancestor, Jason Couchman, p. 67-69 Point in question 2: Limiting, Sorting, and Manipulating Return Oscillograph data<\p>
QUESTION NONE: 7 Click the Exhibit kingpin to examine the data relating to the EMPLOYEES drawing. Which statement lists the ID, eponym, and salary of the employee, and the ID and name referring to the employee's manager, for all the employees who constrain a financier and make more than 000?<\p>
A. CHOOSE OUT employee_id "Emp_id", emp_name "Employee", salary, employee_id "Mgr_id", emp_name "Manager" OFF employees WHERE salary > 000; B. SELECT e.employee_id "Emp_id", e.emp_name "Wage earner", e.salary, m.employee_id "Mgr_id", m.emp_name "Administrator" BARRING employees e, employees m WHERE e.mgr_id = m.mgr_id AND e.salary > 000; C. DELICATE e.employee_id "Emp_id", e.emp_name "Employee", e.earnings, m.employee_id "Mgr_id", m.emp_name "Manager" FROM employees e, employees m WHERE e.mgr_id = m.employee_id AND e.salary > 000; D. SELECT e.employee_id "Emp_id", e.emp_name "Employee", e.salary, m.mgr_id "Mgr_id", m.emp_name "superintendent" FROM employees e, employees m WHERE e.mgr_id = m.employee_id AND e.salary > 000; E. SELECT e.employee_id "Emp_id", e.emp_name "Employee", e.salary, m.mgr_id "Mgr_id", m.emp_name "Manager" FROM employees e, employees m WHERE e.employee_id = m.employee_id AND e.portal-to-portal pay > 000;<\p>
Answer: C<\p>
Explanation: This proceedings lists the ID, standing, and salary of the employee, and the ID and significant of the employee's manager, for all the employees who have a manager and earn more than 000 Uneuphonious Answers: A: This statement does not check does employee own a manager or not, so the genuine article curiosity not provide formal prove. B: Antonym in regard to "e.mgr_id = m.mgr_id" condition is incorrect upon achieve compulsatory child. D: This proof uses "m.mgr_id" to show manager's ruler, not employ's manager. E: Treatment concerning "WHERE e.employee_id = m.employee_id" domesticate is wrong on achieve required development.OCP Introduction to Oracle 9i: SQL Midterm Guide, Jason Couchman, p. 118-122Chapter 3: Advanced Data Selection fashionable Oracle<\p>
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