Patreon | Ko-fi
seen from Switzerland

seen from Slovenia
seen from China

seen from United States
seen from United States

seen from United States
seen from United States

seen from T1

seen from Slovenia
seen from Fiji
seen from Russia
seen from Türkiye
seen from United States
seen from Malaysia

seen from United States
seen from Brazil

seen from Slovenia
seen from Indonesia
seen from United States
seen from Germany
Patreon | Ko-fi

Anya is live and ready to show you everything. Watch her strip, dance, and perform exclusive shows just for you. Interact in real-time and make your fantasies come true.
Free to watch • No registration required • HD streaming
<—
31.2
Cosine (cos)
Parent f(x)
Sibling Graphs
Sine and Cosine graphing method is the same aside from the y-value set up.
View this for trig graphing basics.
Review Examples
[Coming Soon!]
Graphing and Writing Trigonometric Functions
On This Page: Reference formula Graphing transformations of sine Graphing transformations of cosine Graphing transformations of tangent Writing two different equations for sine/cosine
Reference Formula Just like regular transformations in the form of y = af(b(x - c)) + d, except f would be labelled sin, cos or tan.
Graph the following: -2sin3(x - π) + 5 Start with the basic graph of y = sinx
Use the key points to y = sinx to transform the starter graph. y = sinx (0,0) (Ï€/2,1) (Ï€,0) (3Ï€/2,-1) (2Ï€,0) y = -2sinx (multiplying y-coordinate by -2) (0,0) --> (0,0) (Ï€/2,1) --> (Ï€/2,-2) (Ï€,0) --> (Ï€,0) (3Ï€/2,-1) --> (3Ï€/2,2) (2Ï€,0) --> (2Ï€,0) y = -2sin3x (dividing x-coordinate by 3) (0,0) --> (0,0) (Ï€/2,-2) --> (Ï€/6,-2) (Ï€,0) --> (Ï€/3,0) (3Ï€/2,2) --> (Ï€/2,2) (2Ï€,0) --> (2Ï€/3,0) Graph how it looks now.
Now apply the translations. y = -2sin3(x - π) (adding π to x-coordinate) (0,0) --> (π,0) (π/6,-2) --> (7π/6,-2) (π/3,0) --> (4π/3,0) (π/2,2) --> (3π/2,2) (2π/3,0) --> (5π/3,0) y = -2sin3(x - π) + 5 (adding 5 to y-coordinate) (π,0) --> (π,5) (7π/6,-2) --> (7π/6,3) (4π/3,0) --> (4π/3,5) (3π/2,2) --> (3π/2,7) (5π/3,0) --> (5π/3,5) Graph the final graph.
Graph the following: -cos2(x + π/2) - 3 Start with the basic graph of y = cosx
Use the key points to y = cosx to transform the starter graph. y = cosx (0,1) (Ï€/2,0) (Ï€,-1) (3Ï€/2,0) (2Ï€,1) y = -cosx (multiplying y-coordinate by -1) (0,1) --> (0,-1) (Ï€/2,0) --> (Ï€/2,0) (Ï€,-1) --> (Ï€,1) (3Ï€/2,0) --> (3Ï€/2,0) (2Ï€,1) --> (2Ï€,-1) y = -cos2x (dividing x-coordinate by 2) (0,-1) --> (0,-1) (Ï€/2,0) --> (Ï€/4,0) (Ï€,1) --> (Ï€/2,1) (3Ï€/2,0) --> (3Ï€/4,0) (2Ï€,-1) --> (Ï€,-1) Graph how it looks now.
Now apply the translations. y = -cos2(x + π/2) (subtracting π/2 from x-coordinate) (0,-1) --> (-π/2,-1) (π/4,0) --> (-π/4,0) (π/2,1) --> (0,1) (3π/4,0) --> (π/4,0) (π,-1) --> (π/2,-1) y = -cos2(x + π/2) - 3 (subtract 3 from y-coordinate) (-π/2,-1) --> (-π/2,-4) (-pi/4,0) --> (-π/4,-3) (0,1) --> (0,-2) (π/4,0) --> (π/4,-3) (π/2,-1) --> (π/2,-4) Graph the final graph.
Graph the following: y = tan2(x - π/2) + 1 Start with the basic graph of y = tanx
Use y = tanx's zeros and asymptotes. y = tanx (0,0) (π,0) (2π,0) x /= π/2 x /= 3π/2 y = tan2x (dividing x-coordinate by 2) (0,0) --> (0,0) (π,0) --> (π/2,0) (2π,0) --> (π,0) x /= π/2 --> x /= π/4 x /= 3π/2 --> x /= 3π/4 Graph how it looks now.
Now apply the translations. y = tan2(x - π/2) (adding π/2 to x-coordinate) The graph would still look the same. After applying the final translation, the final graph should look like this:
Determine the equation of this graph in the form of a sine function and cosine function.
For sine: Divide it by its period and work from there on. y = -sinx For cosine: Divide it by its period and work from there on. y = cos(x + π/2)