Binomial Coefficients by DevilDoll
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Binomial Coefficients by DevilDoll

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ok this is literally such a long shot but the course im doing is . not explaining this well to me .... does any1 know why this is the number of array accesses? i get 3 cause like . within the inner loop it accesses 3 times but why is it 1/2 n^2 lg n TwT
also ??? how tf does this work if binomial coefficients are n!/((n-k)!k!) ..... is n 3 ?? im so confused <3Â
An Archive of Our Own, a project of the Organization for Transformative Works
Chapters: 1/1 Fandom: Teen Wolf (TV) Rating: Teen And Up Audiences Warnings: Underage Relationships: Derek Hale/Stiles Stilinski Additional Tags: Alternate Universe - High School, Bullying, Happy Ending Summary:
In which brainy freshman Stiles Stilinski wants star quarterback Derek Hale to join the math team, AKA math nerds in love.
An Archive of Our Own, a project of the Organization for Transformative Works
In which brainy freshman Stiles Stilinski wants star quarterback Derek Hale to join the math team, AKA math nerds in love.
Hello! I just wanted to say that I loved your omegamart fics! I know you probably won't update them anymore and I hope you don't feel pressured by this ask, I really just wanted to let you know how much I loved it and nothing more! and while I was going through your fics, I also discovered you were the same author who wrote binomial coefficients (somehow i never made the connection?), which is one of my favorite sterek fics ever, along with clean freak! thank you for sharing your work :)
This ask is probably a billion years old but thank you!
I feel like Omegamart ended in a really bad place…but also the perfect place. So…¯\_(ツ)_/¯
Thanks for the nice words about my stories!

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Binomial Coefficients
Level: A-level Mathematics and aboveÂ
About:Â
A binomial coefficient nCk, also known as a combination or combinatorial number, is the number of unordered ways to choose k items from a set of n items, where n and k are non-negative integers. As the name suggests, they are coefficients in the binomial theorem.
Ever wondered where the entries for Pascal's triangle come from? Â Â Â Â They're binomial coefficients! In this case, n is the row number,and k is the 'column' number. Both n and k start at 0, and k goes up to n in each row.
Our lesson below goes through finding binomial coefficients using your calculator and how to form Pascal’s triangle, and we have some worksheets for you to get the hang of everything. So check them out!
I only just realized that \begin{equation*} \binom n 2 = \frac {n(n - 1)} 2 \end{equation*} but it totally makes sense! If you're counting the 2-element subsets of an \(n\)-element set \(\{x_1, x_2, \dotsc, x_n\}\), you can do that by counting the \(n - 1\) possible 2-element subsets containing \(x_1\), the \(n - 1\) possible 2-element subsets containing \(x_2\) but not \(x_1\), … and the 1 possible 2-element subset containing \(x_{n - 1}\) but not \(x_1\), \(x_2\), … or \(x_{n - 2}\). And \begin{equation} 1 + 2 + \dotsb + (n - 1) = \frac {n(n - 1)} 2 \end{equation} by the well-known formula.
You can also get to \(n(n - 1)/2\) directly by reasoning that there are \(n\) choices for the first element, \(n - 1\) choices for the second element because it has to be distinct from the first, and we divide by 2 because there are two different ways any individual pair of elements can be ordered. This can be easily generalized: in choosing a \(k\)-element subset we have \(n\) choices for the first element, \(n - 1\) choices for the second element, … and \(n - (k - 1)\) choices for the \(k\)th element, and there are \(k!\) ways of ordering any individual \(k\)-element subset, so the number of \(k\)-element subsets is \[ \binom n k = \frac {n (n - 1) \dotsb (n - (k - 1))} {k!} = \frac {n!} {k! (n - k)!}. \]
Can we generalize the member-by-member reasoning too? Well, how many \(k\)-element subsets containing \(x_1\) are there? Exactly as many as there are ways of choosing \(k - 1\) elements from \(n - 1\) (all except \(x_1\))---i.e., \(\binom {n - 1} {k - 1}\). And how many \(k\)-element subsets containing \(x_2\) but not \(x_1\) are there? Exactly as many as there are ways of choosing \(k - 1\) elements from \(n - 2\) (all except \(x_1\) and \(x_2\)). So, continuing on like this, we see that \begin{equation} \binom n k = \sum_{i = 1}^{n - (k - 1)} \binom {n - i} {k - 1}. \end{equation} which is a binomial coefficient identity I didn't know about.
Author:Â DevilDoll
Rating: PG13
Summary:Â In which brainy freshman Stiles Stilinski wants star quarterback Derek Hale to join the math team, AKA math nerds in love.
Words:Â 20783
Status: complete