Sorta kinda starting to look microphone shaped. #diyu87 #diyelectronics
taylor price

blake kathryn
One Nice Bug Per Day

titsay
đŞź

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PUT YOUR BEARD IN MY MOUTH
Today's Document
DEAR READER

#extradirty

Mike Driver
todays bird

JBB: An Artblog!
Alisa U Zemlji Chuda
styofa doing anything

Kiana Khansmith
ojovivo

tannertan36
Sweet Seals For You, Always

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@apmatthews
Sorta kinda starting to look microphone shaped. #diyu87 #diyelectronics

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Remember last year when I got parts for a diy u87? Well now Iâm actually putting it together. Progress! #diyu87
linux: real time vs. user time vs. sys time
The difference between real, user and sys time is something Iâve long had a vague understanding of, but I donât like things to be vague when I can help it. Â So I came up with some experiments to try and produce results based on my understanding:
this program just counts to a billion:
int main(int argc, char *argv[]) { Â int i; Â for ( i = 0; i < 1000000000; i ++ ); Â return 0; }
result: Â lots of user time, little sys time:
real 0m2.736s user 0m2.733s sys 0m0.001s
this program calls stat, a system call, 10 million times:
#include <sys/stat.h> int main(int argc, char *argv[]) { Â int i; Â struct stat buf; Â for ( i = 0; i < 10000000; i ++ ) Â Â stat("/dev/null", &buf); Â return 0; }
result: lots of sys time, little user time:
real 0m5.591s user 0m0.287s sys 0m5.297s
what if we just tell it to sleep a while?
int main(int argc, char *argv[]) { Â sleep(5); Â return 0; }
result: Â little user time, little sys time, but still takes real time:
real 0m5.001s user 0m0.000s sys 0m0.001s
I don't sleep much, myself.
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A True Benefit to Humanity: Hot Chocolate Math
The other day I surrendered to an impulse buy at the grocery store: some Swiss Miss hot cocoa mix. As I read the instructions after returning home, I realized I was ill-equipped for this impulsive purchase as I had no measuring cup to measure the the 8oz of water in Swiss Missâs requirements. Sure, I could just add water to taste but Iâm like an engineer or something, right?
Problem
Though I have no measuring cup, I do have other non-measuring cups such as this one:
Itâs a cylinder with a couple things to account for: 1. The diameter increases from bottom to top 2. The base is solid
Using a measuring device I do have (a ruler) I can measure the top and bottom diameters, the height of the glass, and the height of the base. I also know I need 8 ounces of water, which is 227 grams of water. My only unknown is how high to fill the glass. Thus the problem takes shape:
Solution
The height of the water will depend on its volume. Volume (V) is inversely proportional to density (Ď) by mass (m), and the density of water (Ď_w ) is 1 gram per cubic centimeter. Thus:
The volume of a cylinder from y_0 to y_1 is:
A(y) is the area of the circular cross-section of the cylinder at y. The area is:
r(y) is the radius of the cylinder at y. Since the radius increases linearly we can use the equation of a line for which the slope would be
So in slope-intercept form, r(y) would be:
Plugging everything back in we end up with an equation relating all our quantities:
This integral can be solved by hand but the problem is we end up with a cubic equation that needs to be solved for y_1. And thereâs a constant term, so itâs going to get pretty ugly having to use synthetic division. Whatâs a lazy engineer to do? Use the computer to solve it. In my case I use sagemath
m = 227 pw = 1 y0 = 1.75 h = 14.5 d0 = 5.6 d1 = 6.8 var(ây,y1â) solve(m/pw == integral(pi*((d1-d0)/(2*h)*y + d0/2)^2, y, y0, y1), y1)
sagemath gives me back three answers for y1, which makes sense as itâs a solution to a cubic. Only one of them is a real number and since Iâm not trying to fill the glass with imaginary water, I know itâs the answer Iâm looking for: 9.45cm.
Conclusion
I marked the glass around 9.45cm and I filled it with boiling water to that point. Then I poured the glass into a mug with the hot cocoa mix. After tasting it, I found the approximately 8oz of water too chocolaty and ended up adding water to taste anyways. Well then.

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Support this channel on Patreon: https://www.patreon.com/8bitguy1 In this episode, I take a look at the legendary Roland MT-32 from both the IBM PC games mar...
Some MT-32 love from the 8-bit guy.
Being Unhelpful
On a local Facebook group Iâm a member of, a dad asked for help with this question from his kidâs homework:
Keiko spent the day bird watching and counted 34 more birds in the morning than in the afternoon. Â If she counted a total of 76 birds, how many birds did she count in the afternoon?
Since I am a terrible person I offered him this solution:
Let n â â be the number of birds counted in the afternoon. Let m â â be the number of birds counted in the morning.
Yeah, systems of equations, a bit of matrix math and Cramerâs rule ought to help out your kid with their arithmetic homework...
Le vent se lève, il faut tenter de vivre.
A nylon guitar string has a linear density of 8.57 g/m and is under a tension of 182 N. The fixed supports are D = 96.3 cm apart. The string is oscillating in the standing wave pattern shown in the figure. Calculate the (a) speed, (b) wavelength, and (c) frequency of the traveling waves whose superposition gives this standing wave.
What does the figure look like? I probably just need to know which harmonic or the number of nodes/antinodes.
Your song "Next My Generation" on Hedgehog Heaven is mindblowing and I've been jamming to it since about 2008.
Thanks, I donât think about my ocremix contributions much anymore, but itâs nice when Iâm reminded in a positive way.
cheers.

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Writing a minimalist live electronic music tool similar to seq24 on linux. Hope to get it running on the raspberry pi with an ncurses UI
Algorithmic Dude
I read an article on algorithmic composition from Music and Mathematics which is available here:
Universal Prediction Applied to Stylistic Music Generation
It covers a simple yet effective machine learning algorithm based on data compression that can be applied to algorithmic composition. Â They even included some pseudo-code that I was able to translate easily into Python.
A non-incremental variation of this code is here which uses the example corpus from the article "abababcabdabcdabce" and creates strings of length 10 from it based on its probabilities.
Rather than jump right in to generating music, I used all The Dude's lines from The Big Lebowski as a corpus.  For your enjoyment (or bemusement) here's 10 algorithmically generated lines of dialog of The Dude:
He yelled money all over town including my rug in cash?
Uh and they're gonna kill her!
We're not that yoga?
Is and her Walter what's in the parlance two of police just hey Walter Walter what the fuck are you man!?
Just tell her fucking synagogue.
This is the driver already spent the achievers.
The fucking nihilist ah that some creedence already spent thing?
Peed on my rug in the briefcase.
Amendment fucked it home the friend is this him down a crip...you fuck sympathy!
Wait let me explain something about that shit.
Huh. Â It'll be interesting to see if I'll have better luck with music. Â I just better not use The Eagles as a corpus.
Pumpkin Cravings for orchestra Original by Seth âBeatfoxâ Peelle on Homestuck Vol. 5 Happy Halloween everybody! I have emerged from the shadows to bring you a spooky seasonal treat! And what better time to do so than such a monumental Homestuck date, and sharing the release of an incredible [S] page? Truly the moons of Prospit and Derse saw to it that I would finish this arrangement on such a festive Homestuck eve! Iâve been working on it all month hoping to finish it by Halloween, and it has given me an all-new appreciation for the amount of detail and technique in Beatfoxâs compositions. I hope hearing this orchestration of his 8-bit masterpiece can get that across to you too! I asked Worthikids to scare up an appropriate track art, so be sure to go knock on his door and give him candy for his beautiful contribution!
Babyâs first reblog! This came out a while ago, but it still deserves one. If youâre a Homestuck fan and havenât yet heard Alexander Rosettiâs superb orchestral treatment on my old Pumpkin Cravings tune, do so now!
Sound Physics: Constructive Interference Path
Straight line AB connects two point sources that are 5 meters apart, emit 300 Hz sound waves of the same amplitude, and emit exactly out of phase. What is the shortest distance between the midpoint of AB and a point on AB where the interfering waves cause maximum oscillation of the air molecules?
Since the waves are traveling in opposite directions towards each other but their sources are exactly out of phase, this situation is the same as if they were traveling in the same direction in phase. So we can use this formula relating interference to path length difference:
where fully-constructive interference occurs when Ď = m(2Ď) for m = 0, 1, 2,... âL is the path length difference and Îť is the wave length, which is related to frequency and speed of sound by Îť = v/f. Weâre given the frequency and speed of sound is known so we can rewrite the formula as:
The first instance of fully-constructive interference occurs when Ď = 0, which would require âL = 0. At the midpoint between AB, the path length difference âL is in fact zero. Therefore the shortest distance between the midpoint and where the interfering waves cause maximum oscillation is at 0 meters.
What is the second shortest distance?
Letâs say the midpoint of AB is at x = 0, where point source A is at x = â2.5 meters and point source B is at x = +2.5 meters. Then âL is related to x by
where x is the distance from the midpoint. The second instance of fully-constructive interference occurs when Ď = 2Ď. Letâs solve for x:
What is the third shortest distance?
The third instance of fully-constructive interference occurs when Ď = 4Ď. We can use the same formula as before:
Sound Physics: Pipe Gas
A pipe 0.6 meters long and closed at one end is filled with an unknown gas. The third lowest harmonic frequency for the pipe is 750 Hz. What is the speed of sound in the unknown gas?
The formula for harmonics of a pipe with one closed end is:
where v is the speed of sound, L is the length of the pipe and n = 1,3,5,... Weâre given the length of the pipe and the frequency of the 3rd lowest harmonic (n = 5). Letâs solve for v:
What is the fundamental frequency for this pipe when it is filled with the unknown gas?
Now that we know the speed of sound in the gas we can use the original formula at n = 1 to find the fundamental frequency:

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Sound Physics: Thunder Thunder Thunder Thunder
You can estimate your distance from a lightning stroke by counting the seconds between the flash you see and the thunder you later hear. By what integer should you divide the number of seconds to get the distance in kilometers?
This may actually be useful during a thunderstorm. We take the speed of sound as 343 meters per second, which is 0.343 kilometers per second â roughly close to one third. So we should be able to divide by 3 to approximate.
E.g. if we saw a flash and then 3 seconds later heard the thunder, weâd say the lightning was 1 kilometer away. If we do the actual computation: (0.343 km/s)(3 s) = 1.029 km â 1 km. Close enough!
Sound Physics: Interference
Two sound waves with an amplitude of 12 nm and a wavelength of 35 cm travel in the same direction through a long tube, with a phase difference of Ď/3 rad. What is the amplitude of the net sound wave produced by their interference?
The sum of two waves traveling in the same direction of equal amplitude and frequency differing by phase Ď is
Weâre only interested in the amplitude of the resulting wave, so letâs just take a look at the inside of the brackets and plug in our givens
What is the wavelength of the net sound wave?
When two identical waves (aside from their phase) interfere the resultant wave is only louder or quieter; the frequency and thus the wavelength remain the same. Another way to look at it is from the derivation: The angular wave number k is the same in the resultant wave as the original waves and k is related to wavelength by Îť = 2Ď/k. No change of k means no change of wavelength Îť.
Therefore the wavelength of the net sound wave is 35 cm.
If instead, the sound waves travel through the tube in the opposite directions, what is the amplitude of the net wave?
Two identical waves moving in opposite directions produces standing waves. The formula for a standing wave is:
As you can see in a standing wave the amplitude varies by position x. But the maximum displacement for the overall wave, i.e. the amplitude, is double the original. Therefore the amplitude of the net wave is 24 nm.
What is the wavelength of the net wave?
Like before, same angular wave number of the original waves therefore the same wavelength of 35 cm.