multivariable calculus notes
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multivariable calculus notes

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Finished Chapter 11: Vector Functions and Curves!
What is the unit vector perpendicular to this plane: A = 2i + 4j and ...
The cross product of vectors A and B is a vector perpendicular to A and B.
| i j k |
| 2 4 0 |
| 1 1 -1 |
= i(-4) - j(-2 - 0) + k(2 - 4) = -4i + 2j - 2k
To obtain a unit vector, divide by the magnitude.
Magnitude = √[ (-4)² + 2² + (-2)² ] = √(24) = 2√6
( -4i + 2j - 2k ) / 2√6 = ( -2i + j - k) / √6
THE CORRECT ANSWER IS: (C)
What is the magnitude of a unit vector?
What is the magnitude of a unit vector?
What is the magnitude of a unit vector? A. 1
B. 2
C. 3
D. 4 (more…)
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UNIT VECTOR | NCERT CLASS 12
Math Analysis – Vectors – Find the unit vector Unit Vectors In this tutorial the student will learn how to find the unit vector in the same direction of a given vector.
Constant magnetic solenoid field
Constant magnetic solenoid field
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In [2] the following vector potential
\begin{equation}\label{eqn:solenoidConstantField:20} \BA = \frac{B \rho_a^2}{2 \rho} \phicap, \end{equation}
is introduced in a discussion on the Aharonov-Bohm effect, for configurations where the interior field of a solenoid is either a constant \( \BB \) or zero.
I wasn’t able to make sense of this…
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