Gauge transformed probability current
Gauge transformed probability current
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Question: Gauge transformed probability current ([1] pr. 2.37 (b))
For the gauge transformed Schrodinger equation
\begin{equation}\label{eqn:gaugeTxCurrent:20} \inv{2m} \BPi(\Bx) \cdot \BPi(\Bx) \psi(\Bx, t) + e \phi(\Bx) \psi(\Bx, t) = i \Hbar \PD{t}{}\psi(\Bx, t), \end{equation}
where
\begin{equation}\label{eqn:gaugeTxCurrent:40} \BPi(\Bx…
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