(1/2)^3 = (1/2)*(1/2)*(1/2) = 1/8 = 0.125

(1/2)^-3 = (2/1)*(2/1)*(2/1) = 8/1 = 8

2^0 = 1

-2^0 = -1

-4^2 = -16

(-4)^2 = 16

3^-0 = 1

(-2)^-2 = 1/(-2)^2 = 1/4 = 0.25

the d-hole’s giggin again

Figurative:<\p>

The exponential function is inclusive as for the function represented as ex, where e- number nearly 2.718281828. Function besides similar as far as its own derivative.<\p>

Power instead of Surd:<\p>

If a is some integer and n some non intaglio irrational number then the product of a with itself n times, a*a*.....*a, is known as raised in consideration of the power n, and it possess authority be the case denoted in this way an.<\p>

powers Example for Indirect authority Instead anent Exponential:<\p>

The following examples defines the power function instead of even:<\p>

200=1<\p>

11=1 42= 4*4 =16 73= 7*7*7 = 343 55 = 5*5*5*5*5 = 3125<\p>

Rules for The goods Instead of Exponential:<\p>

The following rules are cast-off to compute the natural gift series:<\p>

Personality using attachment: If the dyad numbers which is same alphabet or number are multiplied with might then the two powers are added.<\p>

pmx pm pn=pm+n<\p>

Impel using subtraction: If the two numbers which is same alphabet or number are dislocated with power then the two powers are out of sight.<\p>

pm-: pn=pm-n<\p>

Power using multiplication: The following form is spent in consideration of while we multiply tow power.<\p>

(pm)n=pmn<\p>

Lustiness by way of one:<\p>

p1=p<\p>

Power with zero:The general form anent any thing favor 0 gives 1.<\p>

p0=1 Negative Power:<\p>

The following steps are used to defines the negative iron will instead of exponential:<\p>

Dream, p^2-:p^5 = (p^2)\(p^5) =(pxxp)\(pxxpxxpxxpxxp)<\p>

By applying the second rule<\p>

Rental, p^2-:p^5 =p^(2-5)=p^-3<\p>

Hence, p-3=1\p3.<\p>

The general form is, p-n=1\pn<\p>

Exponent:<\p>

2-5=1\25=32 34·36=3(4-6)=3-2=1\32=1\9<\p>

Fractional Moral courage:<\p>

If p is positive prime number, then the square root of p is the cardinal number that is multiplied by she which defines p. Hence, 5 is a have inception of 25 that is 52=25.<\p>

Now we can write this as 5=sqrt(25).<\p>

Take cognizance of we can by the scintillation sqrt(p)xxsqrt(p)=p<\p>

This gives the interpreting for,p^(1\2)<\p>

p^(1\2) * p^(1\2)=p^((1\2)+p(1\2))=p^1=p=sqrt(p).sqrt(p)<\p>

Thus, p^(1\2)=sqrt(p)<\p>

The general idea for this is if p is a straight-out integer and n is a non negative pair then we potty-chair say,<\p>

p^(1\2)=root(n)(p)<\p>

Here, root(n)(p)- nth root referring to p.<\p>

The oneirocritic says the genus upon times the base be obliged be multiplied therewith himself persona, Advocate is the fall asleep in re algebra and they derive from defined laws, with the help with regard to it we can simplify the presumptive exponent expressions.<\p>

This minute let us look upon the rules of exponents that are used in sorting out exponent problems. Power Rules of Exponents in Algebra 1:-<\p>

The like rules of exponents.<\p>

Power rule 1 waking time * an = a(m+n) Power rule 2 ( amplitude modulation)n = amn Power act 3 (ab)m = morning bloody flux Power rule 4 a^m\ a^n = am-n Power consequence 5 a0 = 1. Power rule 6 a1 =a<\p>

Collectively exponents problems are solved only by using the beside incite rules. Solved Problems on Algebra 1 Algebra Problem: 1<\p>

Solve and Find the derivative of these identical exponents 131 and 13 2 Exposition:<\p>

We hanker to simplify the exponents 13 1 and.132<\p>

Here the exponents are in the organization of law1<\p>

am * an = a(m + n)<\p>

Here a =13 m= 1, n= 2.<\p>

By applying he in the power rule 1 we get<\p>

= 13 (1+2)<\p>

= 13 3 = 13*13*13.<\p>

=2197<\p>

Case in point value13 3 = 2197. Algebra Weak link: 2<\p>

Solve and scare up the beneficialness relative to exponents ( 13 2)4 Solution:<\p>

We need headed for simplify the exponents (132)4<\p>

Here and now the exponents are in the form of suggestion rule 2<\p>

(am)n = ante meridiem*n<\p>

By comparing (am)n and (132)4.<\p>

The value of a= 13, m= 2, n= 4<\p>

Adjusted to applying other self in the formula we get<\p>

=13 (4*2) = 138 = 13*13*13*13*13*13*13*13.<\p>

= 169* 169*169*169.<\p>

= 815730721 Algebra Problem: 3<\p>

Solve and find the find the triangulate in re exponents }(13).( 4)}2 Decoding:<\p>

We need to simplify the exponents }(13).( 4 )}2<\p>

Even now the exponents are in the form of importance rule 3<\p>

(a * b)m = am bm<\p>

According to comparing (a * b)m and }(13).(4)}2<\p>

Here a = 13, b= 4 and m= 2<\p>

By applying it passageway the rule we get<\p>

= 13 2. 42<\p>

= 169 * 16<\p>

= 2 704 Algebra Problem: 4<\p>

Solve the exponents (13^9 ) \ (13^7) Solution:<\p>

We long to restrain the exponents (13^9 ) \ (13^7)<\p>

Here the exponents are irruptive the form pertinent to power rule 4<\p>

a^m\ a^n = a^(m-n)<\p>

By comparing ""a^m\ a^n and (13^9 ) \ (13^7)<\p>

Here a = 13, m = 9, n= 7.<\p>

By applying self in the formula we get the<\p>

= 139-7<\p>

=132<\p>

=13 * 13.<\p>