#mindteaser

Hi everyone! 👋 I was browsing /r/python and came across this post: The challenge was easy. Provide such an input that if 1 is added to it, it is the instance of the same object but if 2 is added it is not. Solution 1: Custom class The way I personally thought to solve this challenge was this: def check(x): if x+1 is 1+x: return False if x+2 is not 2+x: return False return True class Test(int): def __add__(self, v): if v == 1: return 0 else: return v print(check(Test())) # output: True Let me explain how this works. In Python when we use the + operator Python calls a different dunder method depending on which side of the operator our object is. If our object is on the left side of the operator then __add__ will be called, if it is on the right side then __radd__ will be called. Our Test object will return 0 if Test() + 1 is called and 1 if 1 + Test() is called. The trick is that we are overloading only one dunder method and keeping the other one same. This will help us pass the first if condition. If you take a second look at it you will see that it helps us pass the second if check as well because we simply return the input if it is not 1 so Test() + 2 will always be similar to 2 + Test(). However, after reading the comments, I found another solution which did not require a custom class. Read the full article

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Riddle no 14