#mercatorprojection

this is how indonesia would've looked if it was on top of europe. it'd have stretched from ireland to central kazakhistan.

and this is how big russia would've looked if it was over indonesia.

                    😴 Keep     'Em         Ignorant 😴 At the beginning of our current Civilization which according to some was AFTER 1585 BC, WHEN TES  "Council of Guardians" had established themselves to RUN OUR EARTH, THEY ESTABLISHED              PRELIMINARY ACTIVITIES. PART OF THIS WAS ---- SCANNING AND MAPPING THE EARTH they brought forth from the last warehouse of Technologies          satellites~survey aircrafts~ufo model           surveillance crafts~drones and deployed them to go through the length and breadth of our Earth To Know THE CURRENT EARTH IN DETAILS. The missions were flown~photographs and videos were taken~magnetic~thermo~gravity~SUCH READINGS OF OUR EARTH were taken. The entire data was analysed and         OUR EARTH AT THAT TIME WAS UNRAVELED          T H U S : IN OUR EARTH WERE 🌻 cachés of ancient Technologies located in different places 🌻 cachés of advanced weaponry located in different places 🌻 anomalous zones manifesting such realities as DIMENSIONS~THE OTHER HUMANS~PARAHUMANS~TIME TRAVEL 💿 cachés of dwellings~bones~cultural artifacts~star charts~other relics which SCREAM

Is the Earth a Globe or Flat?

Here is a postulate for determining the flatness or sphericalness of the Earth by determining the circumferences of 5 circles:

1) AB = Arctic Barrier circle circumference 

2) A = Arctic circle circumference

3) E = Equator circle circumference = 24,901miles

4) AA = Antarctica circle circumference

5) AAB = Antarctica Barrier circle circumference

D = Diameter of Earth axis = 18,047/2(3.14159) = 18,047/6.28318 = 2,872.27168 miles

 The equation of a circle passing through three points (x1,y1) (x2,y2) (x3,y3)

Let (j,k) be the coordinates for the center of the circle, with r as its radius.

Then the equation of the circle is:

(x-j)^2 + (y-k)^2 = r^2

(x1-j)^2 + (y1-k)^2 = r^2

(x2-j)^2 + (y2-k)^2 = r^2

(x3-j)^2 + (y3-k)^2 = r^2

 The equation of the circle is:

r = squareroot[(x1-j)^2+(y1-k)^2]

              |x1^2+y1^2  y1  1|

            |x2^2+y2^2  y2  1|

            |x3^2+y3^2  y3  1|

     j = -----------------------------

                  |x1  y1  1|

               2*|x2  y2  1|

                  |x3  y3  1|

            |x1  x1^2+y1^2  y1  1|

          |x2  x2^2+y2^2  y2  1|

          |x3  x3^2+y3^2  y3  1|

  k = ---------------------------------

                     |x1  y1  1|

                  2*|x2  y2  1|

                      |x3  y3  1|

  (j-x1)^2 + (k-y1)^2 = r^2

(j-x2)^2 + (k-y2)^2 = r^2

(j-x3)^2 + (k-y3)^2 = r^2

 (j-x2)^2 - (j-x1)^2 + (k-y2)^2 - (k-y1)^2 = 0

(j-x3)^2 - (j-x1)^2 + (k-y3)^2 - (k-y1)^2 = 0

 j^2-2(x2)*j+(x2)(x2) - j^2-2(x1)*j+(x1)(x1) + k^2-2(y2)*k+(y2)(y2) - k^2-2(y1)*k+(y1)(y1) = 0

j^2-2(x3)*j+(x3)(x3) - j^2-2(x1)*j+(x1)(x1) + k^2-2(y3)*k+(y3)(y3) - k^2-2(y1)*k+(y1)(y1) = 0

 Solve for j and k, then use equation for circle to find r

 r = squareroot[(x1-j)^2+(y1-k)^2]

  ABa=same latitude point north of Asia (Aa)

ABb=same latitude point north of North America (Ab)

ABc=same latitude point north of Europe (Ac)

  Aa=northernmost point on Asia

Ab=northernmost point on North America

Ac=northernmost point on Europe

  AAd=southernmost point on Australia

AAe=southernmost point on South America

AAf=southernmost point on Africa

  AABd=same longitude point south of Australia (AAd)

AABe=same longitude point south of South America (AAe)

AABf=same longitude point south of Africa (AAf)

  ABa: (lat1, long1) = (x1,y1)

ABb: (lat2, long2) = (x2,y2)

ABc: (lat3, long3) = (x3,y3)

  Aa: (lat4, long1) = (x4,y1)

Ab: (lat5, long2) = (x5,y2)

Ac: (lat6, long3) = (x6,y3)

  AAa: (lat7, long4) = (x7,y4)

AAb: (lat8, long5) = (x8,y5)

AAc: (lat9, long6) = (x9,y6)

  AABa: (lat10, long4) = (x10,y4)

AABb: (lat11, long5) = (x11,y5)

AABc: (lat12, long6) = (x12,y6)

Correcting for errors caused by Cartesian system presumptions: 1) curvature of earth is negligible so earth can be presumed “flat” 2) also presumes the grid formed by latitude and longitude is a square. These presumptions are negligible for small distances, however they are compounded over greater distances. Therefore the following offsets for latitude and longitude can be used to compensate for the differences in the earths circumference at the equator and the diameter of the earth at the north/south pole axis:

 Constant ratio latitude offset = earth’s circumference/360degrees/60minutes

24,901miles/360/60=1.15282 miles

 Constant ratio longitude offset = earth’s circumference/360degrees/60minutes

18,047miles/360/60=0.83553 miles

ABa: (lat1 * 1.15282 miles, long1 * 0.83553 miles) = (x1 * 1.15282 miles,y1 * 0.83553 miles)

ABb: (lat2 * 1.15282 miles, long2 * 0.83553 miles) = (x2 * 1.15282 miles,y2 * 0.83553 miles)

ABc: (lat3 * 1.15282 miles, long3 * 0.83553 miles) = (x3 * 1.15282 miles,y3 * 0.83553 miles)

Aa: (lat4 * 1.15282 miles, long1 * 0.83553 miles) = (x4 * 1.15282 miles,y1 * 0.83553 miles)

Ab: (lat5 * 1.15282 miles, long2 * 0.83553 miles) = (x5 * 1.15282 miles,y2 * 0.83553 miles)

Ac: (lat6 * 1.15282 miles, long3 * 0.83553 miles) = (x6 * 1.15282 miles,y3 * 0.83553 miles)

AAa: (lat7 * 1.15282 miles, long4 * 0.83553 miles) = (x7 * 1.15282 miles,y4 * 0.83553 miles)

AAb: (lat8 * 1.15282 miles, long5 * 0.83553 miles) = (x8 * 1.15282 miles,y5 * 0.83553 miles)

AAc: (lat9 * 1.15282 miles, long6 * 0.83553 miles) = (x9 * 1.15282 miles,y6 * 0.83553 miles)

AABa: (lat10 * 1.15282 miles, long4 * 0.83553 miles) = (x10 * 1.15282 miles ,y4 * 0.83553 miles)

AABb: (lat11 * 1.15282 miles, long5 * 0.83553 miles) = (x11 * 1.15282 miles,y5 * 0.83553 miles)

AABc: (lat12 * 1.15282 miles, long6 * 0.83553 miles) = (x12 * 1.15282 miles,y6 * 0.83553 miles)

= (miles,miles)

AB<A

Therefore

If AA<AAB, then the earth is more flat

or

If AA>AAB, then the earth is more spherical

or

If AA or AAB > 24,901 miles, then the earth is more flat

or

If AA or AAB < 24,901 miles, then the Earth is more spherical

Unfortunately, the last math class I took was Calculus in high school and a physics class at UCLA three years ago, so I need assistance creating a formula to determine distance of a curve based off the circle formed by three points on a sphere or flat surface. However, I only began thinking about a scientific way to determine whether the Earth was more round or flat last night. This is what I’ve come up with so far from this morning.  

An airplane flying between any of the points (AAd to AAe or AAe to AAf or AAf to AAd,) on a path on the same plane measuring the nautical miles in between, could then be plugged into the formula to determine the length of the sides of the triangle, based on the distance between two adjacent points on the southern tips of Australia, South America and Africa, to determine the coordinates for the circle’s center which runs along the axis of the North and South poles. 

If the world is a globe then a race around Antarctica is possible, however if the world is flat, then the race will be impossibly long. I’ll give it more thought on another day. Any assistance or ideas would be appreciated.  Thanks.