#learning electronics

/*Date: Feb 28, 2016 **Author: A L **Purpose: This programs takes in Amps and time and returns the **         number of electrons passing through a specific time **         and the current (C) or 1A = 1C\s ** based on information from: **Scherz, P., & Monk, S. (2013). Practical electronics for inventors (3rd ed.). McGraw-Hill. ** */ #include <iostream> #include <math.h>

using namespace std;

int main() {    //init variables    float copper = 0.0;    float timeInSec = 0.0;    float amps = 0.0;    float charge = 0.0;    float numOfElectrons = 0.0;

   //assignments    copper = 1.602 * powf(10.0, -19.0);

   //get user input    cout << "This programs takes in Amps and time and returns the";    cout << "\nnumber of electrons passing through a specific time";    cout << "\nand the current (C) or 1A = 1C\\s." << endl;

   cout << "\nPlease enter the amount of current in amps(A)(eg. 2):";    cin >> amps;    cout << "\nPlease enter the time in seconds (eg. 2):";    cin >> timeInSec;

   //calculations    charge = amps * timeInSec;    numOfElectrons = charge / copper;

//output

   cout << endl << "\nThe charge that passes a given point in " << timeInSec << " seconds is: " << charge << "C";    cout << "\n The number of electrons passing through with a charge of " << charge << "C" << " is " << numOfElectrons;