Tcf part 2 chapter 290
Oh my god Clopeh is now a state alchemist....
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Tcf part 2 chapter 290
Oh my god Clopeh is now a state alchemist....

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Functors
I keep confusing myself with these, and references to List and Maybe as Functors is also confusing so I want to clear this up for myself (and provide a reference for myself in the future in case I forget).
Its not untrue that they’re Functors but they are also Not Functors sort of. They’re more like domains that can be lifted to by Functors if that makes more sense? But since there isn’t a name for these Functors, we call it a List Functor or a Maybe Functor I suppose.
So the Functor Law (from the Haskell Wiki - a Quite Reliable Source) says that Functors must follow two Laws. Identity preservations (fairly trivial), and composition which is a little more complicated. I think Id is fairly trivial so I’m going to ignore Id.
First things first, basics. fmap is defined as fmap :: (a -> b) -> f a -> f b. The f is referring to the (a -> b)
So when we talk about List or Maybe being functors what we mean is that we can take some Function f defined as f :: a -> b and then call fmap f (Maybe a) and we will get Maybe b out of it, which means that we can do a -> b without taking it out of the Maybe “wrapper”. In a purely category theory sense, a functor is the transformation the normal types a and b to the wrapped types Maybe a and Maybe b and since its a functor the morphism (function) is also preserved into the Maybe domain, it turns into a Maybe a -> Maybe b.
Now, lets talk about composition (Id is simple, Id should be the same in all domains, if its a -> a then it certainly should be Maybe a -> Maybe b). Composition says composition of morphisms is preserved so
fmap (f . g) == fmap f . fmap g
I think this is most easy to do by example. Lets even use List as an example so that we can see how functions can effortlessly lift. Composition rule says that if f :: a -> b and g :: b -> c and you fmap f . g which is the same as fmap g ( f a) you will get the same as if you did the two fmaps separately. That means that fmap f . fmap g is the same as fmap g (fmap f a). Ok. Confusing. Lets make a list, lst = [1..26] and lets have some f map integers to letters f :: Int -> Char. Obviously if we fmap f lst we will get a list of of letters back (A-Z if we implement f right) but lets say we also implement g :: Char -> String where each character became a word starting with that letter. So there are two different ways of doing it right? fmap f . g will compose f and g together, which means that it goes Int -> Char -> String which becomes Int -> String and then that function is mapped over the list. Alternatively, we can do fmap f . fmap g - first we want to fmap f lst which gives us a list of Chars and then we map over g mapping Strings from the Chars in the list.
Firstbank Fmap Graduates Inaugral Set Of Management Associates
First Bank of Nigeria Limited, Nigeria’s leading financial inclusion services provider, has graduated 28 successful candidates in its inaugural FirstBank Management Associates Programme (FMAP), virtually held on Tuesday, 30 June 2020 via the Zoom video-conferencing application. The programme which commenced in 2018 had a total of 48 candidates selected from thousands of entries and applications…
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Cam you thirsty hoe
ok I agree this is true about me but can u be slightly more specific as to what warranted this accusation…bc it could be anything
#02: Arthur from Inception

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#01: Anafenza from Magic: The Gathering
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