#flashdev

Madrid Game Conference 19 Marzo: Desarrollar un videojuego en 2 horas #gamedev #quickjam #flappyjam #flashdev

:)  De esta vez, en la Madrid Game Conference, vamos a intentar cambiar un poco el enfoque de las ultimas, y intentar validar la posibilidad de poder desarrollar un videojuego en dos horas, a través de un  flashdev, quickjam o flappyjam, sea como se la quiera llamar.

El objetivo es de evaluar la posibilidad de desarrollar por parte de todos los asistentes a desarrollar un videojuego en el…

If you need to discover the version of your AIR application you can get this info directly of the application descriptor, like this sample method show us:

public function getAppVersion():String { var appXml:XML = NativeApplication.nativeApplication.applicationDescriptor; var ns:Namespace = appXml.namespace(); var appVersion:String = appXml.ns::versionNumber[0]; // AIR below v2.5 use the tag 'version' instead of 'versionNumber' // var appVersion:String = appXml.ns::version[0]; return appVersion; }

Using this same conception we can get any parameter instantiated on application descriptor, like:

- id - filename - name - description - supportedProfiles - installFolder - versionNumber

Some time ago I have needed to find the distance between two points. I found two ways to do this:

1. The easiest way:

With the AS3, the Point class was implemented to make more ease the coordenates manipulation. Inside this class has one method called distance that can be used to find the desired distance.

var point1:Point = new Point(0, 0); var point2:Point = new Point(10, 10); var distance:Number = Point.distance(point1, point2);

2. The optimized way (5x faster):

Surfing on the web I found another method that use the Pythagorean Theorem making execution code speediest. We too can use this method when we dont have a Point instanciated you can use x and y properties of any display object.

var point1:Point = new Point(0, 0); var point2:Point = new Point(10, 10); var distance:Number = distance(point1.x, point1.y, point2.x, point2.y);

This is the magic function:

function distance (x1:int, y1:int, x2:int, y2:int):Number { var dx:int = x2 - x1; var dy:int = y2 - y1; return Math.sqrt(dx*dx + dy*dy) }

Testing and proving:

You must be wondering why the easiest and speediest execution methods are listed here. Ok, I done one simple test to prove the difference of time execution between the two ways where you can see:

Lopping 10000000 times in each method this results are printed:

Finding distance using Point.distance: [distance=14.142135623730951, execution time: 5673ms]