the four things you need to pass a set theory class
part 5 of set theory (toc)
So several people have been on my case for not posting enough. All right, you caught me. But I've been really overwhelmed with my imminent graduation, graduate school applications, and my research... but, hey, time's a-wastin' and you aren't here to hear me complain.
So my set theory professor has a qualifying exam that every student must ace in order to pass the class. And I'm serious about acing. I forgot the exact mark you need to get, but I think it's somewhere north of 95%. It's pretty fair though, because we are told in advance exactly the flavour of questions we're going to get. Well...if he's emphasising these things so heavily, they must be important. Onto the blog they go.
The first problem is a write off. It's basically an application of the subset theorem. It might be something like "given A is a set, prove A x A is a set". And then you would notice that an element of A x A is of the form {{a}, {a, a'}}, which is a subset of the power set of A, PA. Then a set of these things, e.g. A x A, would be a subset of PPA. By the subset axiom, A x A is a set. Easy.
(Time out: I haven't actually defined ordered pairs yet for you guys. The concept of an ordered pair is pretty simple: it's something of the form <a, b>, where knowing a, knowing b, and knowing the order they go in completely determines the ordered pair. There were several propositions on how to go about formally defining this idea, but the one that stuck is to let <a, b> = {{a}, {a, b}}. Then, the set {a, b} completely determines the elements of the ordered pair, and the element in the singleton, i.e. {a}, is the first element in the ordered pair. Like I said, there have been other equally valid formulations that work, and it might be interesting to look them up. This method is popular because it is convenient and easy to work with.
Then, given two sets A and B, A x B is defined to be the set of all ordered pairs <a, b> where a comes from A and b comes from B. This set is the cross product of A and B.)
The third question is an application of Zorn's Lemma. Oh yeah! Zorn's Lemma is some new material for this blog. Let's do a quick refresher on the axiom of choice. At this point in the class, we've got several alternate formulations of the axiom of choice:
For any function R, there is a function f contained in R, with the same domain as R.
If H is a function defined on I, and H(i) is nonempty for every i ∈ I, then there is a function with domain I and f(i) ∈ H(i). In other words, the cross product of nonempty sets is nonempty.
For any set A, there is a function f whose domain is the set of nonempty sets of A, and f(B) ∈ B for all nonempty B ⊆ A. In this case, f is called the choice function on A.
For sets C, D, either there is a one to one function from C into D, or there is a one to one function from D into C. We say C is dominated by D if there is a one to one function from C into D. This formulation says that, given a pair of sets, one must be dominated by another.
If A is a set so that for every chain B ⊆ A, we have that the union over B is an element of A, i.e. ∪B ∈ A, then A has a maximal element. This statement is Zorn's Lemma. There's quite a few new terms in this one, so let's go through it slowly. B is a chain iff for any C, D in B, either C ⊆ D or D ⊆ C. An element M ∈ A is maximal if M is not a subset of any other set in A.
So the third question on the qual is simply an application of Zorn's Lemma: "given a set A with some qualities, show that A contains a maximal element". You must show that A satisfies the conditions for Zorn's Lemma, i.e. for every chain in A, the union over the chain is an element of A (has whatever qualities qualify a set to be in A).
The last question is just an identification of the axiom of choice within a proof or statement. This question is generally pretty easy: you just look for some statement "for every A, there is a B, so let BA be this B". This statement evokes the axiom of choice if there are an infinite amount of As. In general, you are looking for some sort of choice or specification of one element out of a group of similar elements--and this choice is made for an infinite number of groups.
I apologise again for the dry spell and this relatively short post. To be honest, I'm not sure I have an incredibly solid footing when it comes to the later material we've done in this class. I've also been unfortunately preoccupied with a whole lot of other stuff that's gone down in my life. When I have time to sit down and really review set theory, I will definitely be using my blog to do some of the legwork. Look forward to it (or not). Until next time, chicas.
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