#binary addition

Explore how logic gates add two 4-bit numbers. Toggle input bulbs for A and B, watch carries ripple through XOR/AND/OR gates, and read the live binary/decimal sum. Interactive 4-Bit Adder :: Logic Gate Visualizer

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C Program to Perform Binary Addition of Strings and Print it

#include <stdio.h> #include <string.h> /* global variables */ char s1[10], s2[10], s3[10]; int i, k; char carry = '0'; /* function prototype */ void binary_add(char *,char *); void main() printf("enter string1\n"); scanf(" %[^\n]s", s1); printf("enter string2\n"); scanf(" %[^\n]s", s2); binary_add(s1, s2); printf("binary addition of number is\n"); if (carry == '1') s3[i] = '1'; for (i = 1;i <= k + 1;i++) printf("%c", s3[i]); printf("\n"); else for (i = 1;i <= k + 1;i++) printf("%c", s3[i]); printf("\n"); /* function to add two binary numbers in a string */ void binary_add(char *s1, char *s2) char *p1, *p2; p1 = s1; p2 = s2; k = strlen(s1); for (;*p1 != '\0' && *p2 != '\0';p1++, p2++); p1--; p2--; s3[k+1] = '\0'; for (i = k + 1;i >= 1;i--, p1--, p2--) if (*p1 == '0' && *p2 == '0'&& carry == '0') s3[i] = (*p1 ^ *p2) ^ carry; carry = '0'; else if (*p1 == '0' && *p2 == '0' && carry == '1') s3[i] = (*p1 ^ *p2)^ carry; carry = '0'; else if (*p1 == '0' && *p2 == '1' && carry == '0') s3[i] = (*p1 ^ *p2)^ carry; carry = '0'; else if (*p1 == '0' && *p2 == '1' && carry == '1') s3[i] = (*p1 ^ *p2)^ carry; carry = '1'; else if (*p1 == '1' && *p2 == '0' && carry == '0') s3[i] = (*p1 ^ *p2)^ carry; carry = '0'; else if (*p1 == '1' && *p2 == '0' && carry == '1') s3[i] = (*p1 ^ *p2)^ carry; carry = '1'; else if (*p1 == '1' && *p2 == '1' && carry == '0') s3[i] = (*p1 ^ *p2)^ carry; carry = '1'; else s3[i] = (*p1 ^ *p2)^ carry; carry = '1';

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