#1089

PT: 1089: Transprincessinity, or transprincessine /end PT

DEFINITION ⦂⠀The transfeminine/transmasculine/etc. version of princessinity (Tumblr link).

PT: Definition: The transfeminine/transmasculine/etc. version of princessinity (Tumblr link). /end PT

ADDITIONAL ⦂⠀Coined on the 24th of April, 2026.

PT: Additional: Coined on the 24th of April, 2026. /end PT

TAGGING ⦂⠀@c1rcus-of-silliness @dearestchild @goregender @radiomogai

Pick any 3-digit number a where the first and last digits are different.

Reverse the number to get b

Subtract the smaller from the larger (a - b or b - a) to get a new number c

Reverse that result to get a new number d

Add them (c + d)

If you follow this process, you'll always get 1089.

For example, let's choose the number 532. Reversing this number gives 235. Subtracting the smaller from the larger, we get 532 - 235 = 297.

Then reversing that result give 792. Adding 792 to 297 gives 1089.

Why does this work?

Let your number be:

100a + 10b + c

with a > c.

Reversing the digits gives

100c + 10b + a

Subtracting the two gives

(100a + 10b + c) - (100c + 10b + a) = 99a - 99c = 99(a-c)

This means that the result of this subtraction is always a multiple of 99.

What's interesting is that multiple of 99 between 100 and 999 have a special digit structure. When you reverse them and add, they collapse to 1089.

To see why, note that 99k = 100k - k

This subtraction forces a very specific digit pattern. For example:

99 * 3 = 300 - 3 = 297

99 * 7 = 700 - 7 = 693

In general, every such number looks like:

(hundreds digit) = k-1, middle digit = 9 (after borrowing), (ones digit) = 10 - k

The number thus has the form:

(k-1) 9 (10-k)

Reversing it gives:

(10-k) 9 (k-1)

Adding them gives

9 in the ones digit

Tens digit is 9 + 9 = 18 (so leave the 8, carry the 1)

Hundreds is (k - 1) + (10 - k) + 1 (from carry) = 10

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