Geometric Problem
1.) Compute radius R from the lengths c and d. 2.) Which invariant do a and b fullfill?
Solution: 1.) R=c*d/(c+d) 2.) a*b=R²
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@gamutra
Geometric Problem
1.) Compute radius R from the lengths c and d. 2.) Which invariant do a and b fullfill?
Solution: 1.) R=c*d/(c+d) 2.) a*b=R²

Anya is live and ready to show you everything. Watch her strip, dance, and perform exclusive shows just for you. Interact in real-time and make your fantasies come true.
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Bag I was able to screen print at a stand at the celebration of "100 Jahre Dortmunder U".
Die Pilze sind dieses Jahr wieder zurück gekommen!
Squaring the Circle 😊
The classic construction with only compass and lineal is impossible. But if you allow one extra angle of arccos(sqrt(π)/2)≈27,597°, then you can square any circle. The area of this circle and square are both π! This property holds true under uniform scaling and is valid for any radius of the circle.
Mushrooms seen on my way home. There was a large three beside them in the past, which was removed. I think remains of the large roots are still in the ground and are broken down by the mycelia.

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Mirroring complex numbers
I found a nice formula to mirror a point z regarding a line G given by the point P and direction s. z,P,s are complex numbers. The mirror point can be computed by
Small snail I found resting on a leaf in sunshine after light rain.
I bought a cheap planting set for cacti and got lucky with the results.
I added some extra earth at the bottom of the pot to get this result.
This is too small for the cacti and I replanted them, and replanted another cactus that I had before while I was at it, too. 😊
I am working on a new double layered cap. 100% sheep wool, too.
This cap will be very warm!
Tried my hand at Bing Image Creator

Anya is live and ready to show you everything. Watch her strip, dance, and perform exclusive shows just for you. Interact in real-time and make your fantasies come true.
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I have just learned how to knit socks. This is the first sock I ever made!
Nice little equality, which allows to swap out an exponent
The proof can be done in one line, if you use “a=e^ln(a)”, “log_c(a)=ln(a)/ln(c)”, and “(x^y)^z=x^(y*z)”.
I visited the beach of Boltenhagen. Here some impression pictures.
I worked a long time on a gift for my mother, which she could use to keep her shoulders warm.
GEM-ENCRUSTED INSECT ART BY FRENCH ARTIST STEEVEN SALVAT
Read more in the following article for more information or visit the homepage of the artist at https://www.steeven-salvat.com/ :
https://www.beautifullife.info/art-works/gem-encrusted-insect-art-by-french-artist-steeven-salvat/

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3D extension of DIN A paper format
The DIN A paper format has the properties that DIN A0 has an area of 1m², the next format can be generated by splitting the long side, while the ratio stays the same.
This way DIN A1, A2, and so on can be generated by splitting the paper at the long side.
This caused me to think if an extension of the principle would be possible for 3D?
The result of my computations is something I want to call the DIN A0 brick:
It has the length dimensions \(\{\sqrt[3]{2}m,1m,\frac{1}{\sqrt[3]{2}}m\}\) and a volume of 1m³. The ratios of the sides ordered by length stay the same after an even splitting of the longest side.
Another version of the previous carry-all.