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CHEMISTRY - Most likely not being helpful -- also, private posts not working for me so it is public.

This is all you need to determine the activation energy.

This equation above is converted from below.

ln k = ln A - Ea/(RT)

http://www.chemguide.co.uk/physical/basicrates/arrhenius.html

This webpage helps a LOT!

http://www.chemguide.co.uk/physical/basicrates/pressure.html#top

Once you calculate the RT value, you can place that in the equation for with the pressure and get the activation energy.

I hope that it didn't screw you up. This website is awsome.

Oh, and I hate physcial chemisty! I was more of an anaytical gal, but it is all the same in the end.

Make sure the units equal in the end!

I probably didn't help at all.

#soy was a chemist #WAS!!!!!#shinr-rufus