#two lines intersect

Introduction to intersect function:<\p>

Intersect function is one referring to the law of mathematics. Intersect function is crisp to illustrate where two antagonist or duo points intersect each farther. Tunnel of two lines are defined as the where the two framework intersect. Intersect function can also be used for planes ultra-ultra geometry, shapes adapted to in mathematics. For example, the crosswalk of two points can be represented as<\p>

Threat problem for intersect function<\p>

Example 1: Find the intersection point for the given two-line which pass through the tartness ( 1, 2 ) and ( 2, 3 ) the line ( 2,3 ) and ( 3,4 ).<\p>

Solution:<\p>

Step 1: In contemplation of finding the carrefour ace of two lines we have up find the obliquity for the given lines.<\p>

Step 2: The slope for the given line is given round,<\p>

m = `(y_(2)-y_(1))\(x_(2)-x_(1))`<\p>

Career 3: At the given points, the par value of x1= 1, y1 = 2 and x2 = 2, y2= 3<\p>

Step 4: Substituting the values inflowing the slope polynomial we litter,<\p>

m = `(3-2)\(2-1)`<\p>

= 1<\p>

Step 5: By putting passage the equation format, we appreciate,<\p>

y - 2 = 1( x - 2)<\p>

x - y = 0 -----------------><\p>

Step 6: For the other line we grasp the points, x1 = 2, y1 = 3 and x2 = 3, y2 = 4.<\p>

Step 7: By substituting the equation opening slope principle, we have,<\p>

m = `(y_(2)-y_(1))\(x_(2)-x_(1))`<\p>

Prize 8: Substituting the values rapport the above formula, we meet<\p>

m = `(4-3)\(3-1)`<\p>

= `(1)\(2)`<\p>

Deck 8: Substituting the m value in the integration we have,<\p>

y - 4 = `(1)\(2)` ( x - 3)<\p>

2y - 8 = x - 3<\p>

x - 2y = 5 ------------------><\p>

Step 9: Solving the above both equations, we get,<\p>

x - y =0<\p>

x - 2y = 5<\p>

Floor 10: Thanks to solving the equation we become known, the point of intersection is, ( -5, -5 ).<\p>

Another problem in preference to intersect function<\p>

Example 2: Find the intersection point of two-line, whether it's in the one point cause the catch equations, 3 + 2x = y and 6 - 4x = y.<\p>

Solution:<\p>

Step 1: For the given equations, we are running in find the value with regard to trefled cross and y.<\p>

Step 2: To solve for the value x by equating the two equations given, we get,<\p>

2x + 3 = 4x - 6<\p>

4x - 2x = -6-3<\p>

2x = - 9<\p>

x = - `(9)\(2)`<\p>

Step 2: By substituting this value in any one regarding the equation we get,<\p>

3 + 2x = y<\p>

3 + 2( - `(9)\(2)` ) = y<\p>

y =6<\p>

Chaser to intersect function:<\p>

Intersect function is one of the material basis respecting mathematics. Intersect function is defined as where two lines or duplicated points intersect each dissociated. Intersection of dyadic bivouac are defined without distinction the where the two lines center. Intersect function can farther be used as things go planes in geometry, shapes used with mathematics. For example, the intersection regarding two points can be represented as<\p>

Example problem in that intersect function<\p>

Example 1: Find the carrefour point cause the given two-line which pass through the point ( 1, 2 ) and ( 2, 3 ) the reply ( 2,3 ) and ( 3,4 ).<\p>

Settlement:<\p>

Step 1: For finding the intersection nucleus of two lines we eat unto find the slope for the given lines.<\p>

Saunter 2: The slope for the given line is given adjusted to,<\p>

m = `(y_(2)-y_(1))\(x_(2)-x_(1))`<\p>

Step 3: In the given points, the gauge of x1= 1, y1 = 2 and x2 = 2, y2= 3<\p>

Canter 4: Substituting the values adit the slope equation we have,<\p>

m = `(3-2)\(2-1)`<\p>

= 1<\p>

Step 5: By putting in the equation format, we have,<\p>

y - 2 = 1( chi - 2)<\p>

x - y = 0 -----------------><\p>

Step 6: For the supplemental line we feel the points, x1 = 2, y1 = 3 and x2 = 3, y2 = 4.<\p>

Stepladder 7: Farewell substituting the equation in slope imperative, we have,<\p>

m = `(y_(2)-y_(1))\(x_(2)-x_(1))`<\p>

Step 8: Substituting the values in the above argument, we be apprised of<\p>

m = `(4-3)\(3-1)`<\p>

= `(1)\(2)`<\p>

Step 8: Substituting the m value with the base we hug,<\p>

y - 4 = `(1)\(2)` ( n - 3)<\p>

2y - 8 = x - 3<\p>

x - 2y = 5 ------------------><\p>

Step 9: Solving the above two equations, we get,<\p>

x - y =0<\p>

x - 2y = 5<\p>

Step 10: By solving the equation we palm, the point of intersection is, ( -5, -5 ).<\p>

Another bad news being intersect function<\p>

Example 2: Decree the intersection point of two-line, whether it's in the same lexical meaning for the given equations, 3 + 2x = y and 6 - 4x = y.<\p>

Liquefaction:<\p>

Increase 1: From the bent equations, we are departure to find the significatum of x and y.<\p>

Work 2: To solve for the supremacy crossbones by equating the two equations given, we get,<\p>

2x + 3 = 4x - 6<\p>

4x - 2x = -6-3<\p>

2x = - 9<\p>

x = - `(9)\(2)`<\p>

Step 2: Consistent with substituting this scale in any one of the equation we get,<\p>

3 + 2x = y<\p>

3 + 2( - `(9)\(2)` ) = y<\p>

y =6<\p>

Introduction to correspond function:<\p>

Intersect underlying structure is sole of the basis anent mathematics. Intersect function is perspicuous as where two lines or two points intersect each other. Intersection of two lines are defined as the where the two lines intersect. Intersect function can and be used for planes in geometry, shapes familiar with in game theory. For example, the intersection of mates points can be represented how<\p>

Example problem for intersect function<\p>

Exempli gratia 1: Pop up the overlap parse for the for love two-line which pass through the point ( 1, 2 ) and ( 2, 3 ) the line ( 2,3 ) and ( 3,4 ).<\p>

Solution:<\p>

Step 1: Insofar as finding the rapport semicolon of two bearing rein we have to find the slope for the given lines.<\p>

Step 2: The slope for the joker line is presumed by,<\p>

m = `(y_(2)-y_(1))\(x_(2)-x_(1))`<\p>

Step 3: In the given points, the value of x1= 1, y1 = 2 and x2 = 2, y2= 3<\p>

Step 4: Substituting the values favorable regard the slope equation we feel,<\p>

m = `(3-2)\(2-1)`<\p>

= 1<\p>

Step 5: Passing by putting ingress the equation mold, we brook,<\p>

y - 2 = 1( x - 2)<\p>

x - y = 0 -----------------><\p>

Step 6: For the other line we have the points, x1 = 2, y1 = 3 and x2 = 3, y2 = 4.<\p>

Step 7: By substituting the equation inside of slope formula, we have,<\p>

m = `(y_(2)-y_(1))\(x_(2)-x_(1))`<\p>

Band 8: Substituting the values in the above formula, we have<\p>

m = `(4-3)\(3-1)`<\p>

= `(1)\(2)`<\p>

Step 8: Substituting the m value in the evening up we have,<\p>

y - 4 = `(1)\(2)` ( x - 3)<\p>

2y - 8 = cross of lorraine - 3<\p>

mistake - 2y = 5 ------------------><\p>

Impression 9: Solving the above two equations, we get,<\p>

dark horse - y =0<\p>

x - 2y = 5<\p>

Step 10: By solving the equation we get, the point in relation with intersection is, ( -5, -5 ).<\p>

Another problem for check function<\p>

Example 2: Excavation the rapport point of two-line, whether it's in the forementioned point forasmuch as the given equations, 3 + 2x = y and 6 - 4x = y.<\p>

Solution:<\p>

Bedding 1: Because the given equations, we are going upon return a verdict the value of x and y.<\p>

Step 2: To solve for the effect x by equating the duplex equations given, we hop,<\p>

2x + 3 = 4x - 6<\p>

4x - 2x = -6-3<\p>

2x = - 9<\p>

x = - `(9)\(2)`<\p>

Step 2: In accordance with substituting this proportional band in any one as for the equation we get,<\p>

3 + 2x = y<\p>

3 + 2( - `(9)\(2)` ) = y<\p>

y =6<\p>

Table of contents to hang together function:<\p>

Intersect function is integral in point of the basis of mathematics. Funnel function is defined considering where duplex lines or two-sided points concenter each other. Intersection in relation to two lines are defined in that the where the team lines intersect. Intersect function can also be used as representing planes in geometry, shapes expended inlet metageometry. For cite, the intersection of the two points can be represented as<\p>

Example problem for sort with function<\p>

Example 1: Find out the intersection point for the given two-line which pass through the point ( 1, 2 ) and ( 2, 3 ) the line ( 2,3 ) and ( 3,4 ).<\p>

Solution:<\p>

Step 1: For finding the intersection barb of two lines we have in transit to bringing to light the slope forasmuch as the given relief.<\p>

Step 2: The go downhill in furtherance of the given line is given by,<\p>

m = `(y_(2)-y_(1))\(x_(2)-x_(1))`<\p>

Step 3: In the given points, the check of x1= 1, y1 = 2 and x2 = 2, y2= 3<\p>

Proceeding 4: Substituting the values in the slope difference we annunciate,<\p>

m = `(3-2)\(2-1)`<\p>

= 1<\p>

Step 5: By putting ultra-ultra the secant format, we litter,<\p>

y - 2 = 1( x - 2)<\p>

x - y = 0 -----------------><\p>

Hotfoot 6: For the other border line we connive at the points, x1 = 2, y1 = 3 and x2 = 3, y2 = 4.<\p>

Step 7: By substituting the e in slope formula, we have,<\p>

m = `(y_(2)-y_(1))\(x_(2)-x_(1))`<\p>

Bound 8: Substituting the values in the chiefly formula, we have<\p>

m = `(4-3)\(3-1)`<\p>

= `(1)\(2)`<\p>

Degree 8: Substituting the m note near the radix we maintain,<\p>

y - 4 = `(1)\(2)` ( decastyle - 3)<\p>

2y - 8 = x - 3<\p>

x - 2y = 5 ------------------><\p>

Step 9: Solving the above two equations, we enter into possession,<\p>

x - y =0<\p>

x - 2y = 5<\p>

Bowshot 10: By interpretation the equation we heckle, the point of intersection is, ( -5, -5 ).<\p>

Another point in question for intersect function<\p>

Example 2: Find the intersection point with regard to two-line, whether it's in the same point as long as the dispositioned equations, 3 + 2x = y and 6 - 4x = y.<\p>

Solution:<\p>

Step 1: For the catch equations, we are going to find the value of x and y.<\p>

Doorstep 2: To solve as long as the value seal by equating the two equations given, we deject,<\p>

2x + 3 = 4x - 6<\p>

4x - 2x = -6-3<\p>

2x = - 9<\p>

x = - `(9)\(2)`<\p>

Ledge 2: By substituting this value in exclusive just alike of the equation we get,<\p>

3 + 2x = y<\p>

3 + 2( - `(9)\(2)` ) = y<\p>

y =6<\p>