#oxidizing agent

A new study published in Environmental Science & Technology found that when slathered-up beachgoers go for a dip, the traces of sunscreen that wash off into the ocean poison phytoplankton, the microscopic plant life that anchor the marine food web. 

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Here’s the problem: at those levels, hydrogen peroxide is so toxic to phytoplankton that it caused their numbers to crash by around 80%. 

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Not only are phytoplankton a crucial part of a balanced ecosystem, they also perform a critical role in the Earth’s carbon cycle. Like land plants, phytoplankton get their energy by photosynthesis—swapping carbon dioxide in seawater for oxygen. This lets the sea absorb carbon dioxide from the atmosphere, stalling the effects of burning fossil fuels on air temperatures.

In the previous post we have discussed about What is Differential Calculus and In today's session we are going to discuss about What is imaginary number. In this blog we will see the Imaginary Number definition. Any numbers which is having iota (i) symbol with it are said to be imaginary numbers. Basically imaginary number is denoted as the symbol ‘i'. Now we will understand the concept of solving imaginary numbers. We will solve imaginary numbers step by step:

Step 1: First of all we have an expression which has imaginary values for solving imaginary numbers. Let we have an expression (7 – i) (4 + 9i).

Step 2: In above given expression imaginary number is present. Now multiply first term of first set to each value of the next set and we have to follow same procedure for the second term of first set. On multiplying above number can be written as:

= (7 – i) (4 + 9i),

= (7 * 4) + (7 * 9i) - (4 * i) – 9i2,

Step 3: Then simply multiply the above and also find value of ‘i’. On further solving we get:

= (7 * 4) + (7 * 9i) - (4 * i) – 9i2,

= 28 + 63i – 4i – 9i2, as we know that the value of i2 is -1. Put -1 in place of i2. So it can be written as:

= 28 + 63i – 4i - 9 (-1); on further solving we get:

= 28 + 59i + 9. In this way we can solve the imaginary expression.

For imaginary number one condition is given as:

Value of i = √-1, Here if we use iota in the expression then we can write the square root of negative numbers. For example: (√ a (√ b)), it can also be written as √ ab.