#new tiling

I am now 3D printing a small playset of tiles, in the shape of the new convex pentagon which tiles the plane.  

Yes, I’m aware I need to replace my blue tape.  I’m lazy.

Here’s my openscad code - I *think* I got it right.  I read the side lengths and angles off of wikipedia (it’s tiling number 15 on the list), put the easiest-looking vertex at (0,0), and then did basic trig until I worked out where all the other vertices were.  They’re 2 layers thick and 1 cm on a side.  That’s probably too small, but I want them now, and small is fast.

layer = 0.41; linear_extrude(height=2*layer) scale(10) polygon (    points=[[0,0],[sqrt(3),1], [sqrt(3)/2, 3/2], [-1,1], [-1,0]],    paths=[[0,1,2,3,4,0]] );