Extra info on the dice thing: in particular, you're more likely to get the avg of 7 using 2d6 (I believe the other ask mentioned this too). Basically, with 1d12 the expected value would be 6.5, but you can't roll that so in practice it means in the long run you should see approximately the same number of 6's and 7's. With 1d6, the expected value is 3.5, so you would expect there to be an approximately equal amount of 3's and 4's. If you roll 2 of these dice, that's twice as many 3's and 4's and they can combine.
So, you'll see more (3,3), (3,4), (4,3), and (4,4) pairs than other pairs. And if you notice, half of those give you 7, while one gives 6 and one gives 8. This means given that the total you roll is in the range 6 to 8, you are 75% likely to get 7 or 8 thanks the two ways to get 7. But with 1d12 you can only get 6, 7, and 8 one way each, and you're competing with the remaining 9 other outcomes of the die, meaning it is less likely you get the avg of 7.
ohh i see... man, there's a lot more to dice than i thought!
