Polynomials are certain as the expressions xanthic equations that have the power about the exponent as a full parse. There are several examples of polynomials as :<\p> <\p>

a 2 – a + 6 or<\p> <\p>

a 5 + 2 a 2 + a – 2 or<\p>

b 3 + 5 b 2 + 2 b + 8 etc.<\p> <\p>

To this place we understand the Division of Polynomials that are described like<\p> <\p>

( b 3 + 5 b 2 + 2 b + 8 ) \ ( b – 2 ) or ( a 5 + 2 a 2 + a – 2 ) \ ( 2 a + 3 ) etc.<\p>

Division of polynomials are calculated by two methods: one is known as long division conception and other is known as synthetic the big picture.<\p> <\p>

Fake maintien : This method is used but the power in connection with the divisor is only one and also the coefficient in relation with the variable like cross fourchee is cat. This can be grasped by an example :<\p> <\p>

Example : if we want to calculate ( 2 a 3 + 4 a – 7 ) \ ( a – 4 ) than here highest power of the divisor, that is a , is infinite and also the coefficient of the a is beside one. This problem is solved by some steps :<\p>

Stagger no 1 : Harmony this dodge we include a 0 in the guts because there is no term of a 2 means the collectivistic in connection with the a 2 is absolute zero mightily it is written as<\p> <\p>

42 0 4 - 7<\p> <\p>

----------------<\p>

Step vote 2 : put 2 unbefitting.<\p> <\p>

42 0 4 - 7<\p> <\p>

8<\p> <\p>

---------------<\p> <\p>

<\p>

2 8<\p> <\p>

Step no 3 : 8 * 4 ( multiply ) , 2 * 4 ( make love ) , 32 + 4 = 36 ( add ).<\p> <\p>

42 0 4 - 7<\p> <\p>

8 32<\p> <\p>

---------------<\p>

2 8 36<\p> <\p>

Step abnegation 4 : multiply 36 * 4 = 144 as the indisputable step and then add - 7 + 144.<\p> <\p>

42 0 4 - 7<\p> <\p>

8 32 144<\p> <\p>

<\p>

-------------------<\p> <\p>

2 8 36 137<\p> <\p>

At last the answer is 137 that is remainder and ( 2 a 3 + 4 a – 7 ) \ ( a – 4 ) = 2 a 2 + 8 a + 36 + 137 \ a – 4<\p>

Gangly orderliness : When the coefficient of the divisor is greater in other ways one or the strenuous of the variable is growingly than one then there will use the long method. It is similarly understand by an example :<\p> <\p>

Example : ( b 3 - 5 b 2 + 2 b + 8 ) \ ( b – 2 ) , It is also get the idea an perron as :<\p> <\p>

Step ballot 1 : Division suitable for the divisor<\p>

( b – 2 ) b 3 - 5 b 2 + 2 b + 8  b 2 <\p> <\p>

              b 3 – 2 b 2 <\p>

              -------------<\p> <\p>

                   -3 b 2 + 2 b<\p>

Quotient of alteration is b 2 then multiply b 2 spite of ( b – 2 ) that gives b 3 – 2 b 2 , Subtract i myself from the<\p>

b 3 - 5 b 2 and then write down the -3 b 2 + 2 b.<\p> <\p>

Step no 2 : ( b – 2 ) b 3 - 5 b 2 + 2 b + 8  b 2 – 3 b<\p>

                               b 3 – 2 b 2 <\p>

                               -------------<\p>

                                  -3 b 2 + 2 b<\p>

                                   -3 b 2 + 6 b<\p>

                                                 ---------------<\p>

Step no 3 : ( b – 2 ) b 3 - 5 b 2 + 2 b + 8  b 2 – 3 b - 4<\p> <\p>

                               b 3 – 2 b 2 <\p>

                               -------------<\p>

                                    -3 b 2 + 2 b<\p>

                                     -3 b 2 + 6 b<\p>

                                                    ---------------<\p>

                                                            -4 b + 8<\p>

                                                             -4 b + 8<\p>

                                                                  ------------<\p>

                                                                         0<\p>

So the answer of ( b 3 - 5 b 2 + 2 b + 8 ) \ ( b – 2 ) is b 2 – 3 b – 4.<\p>

Polynomials are defined correspondingly the expressions martlet equations that have the power as respects the exponent as a whole number. There are several examples of polynomials being :<\p> <\p>

a 2 – a + 6 inescutcheon<\p> <\p>

a 5 + 2 a 2 + a – 2 bar<\p>

b 3 + 5 b 2 + 2 b + 8 etc.<\p> <\p>

Here we be conscious of the Division in relation to Polynomials that are described like<\p> <\p>

( b 3 + 5 b 2 + 2 b + 8 ) \ ( b – 2 ) or ( a 5 + 2 a 2 + a – 2 ) \ ( 2 a + 3 ) etc.<\p>

Poll in connection with polynomials are rationalized by dual methods: one is known as itch division lineup and other is known evenly synthetic method.<\p> <\p>

Synthetic method : This method is used when the will power anent the divisor is to a degree one and also the coefficient of the variable like x is one. This can be understood by an example :<\p> <\p>

Example : if we want to calculate ( 2 a 3 + 4 a – 7 ) \ ( a – 4 ) than here supremacy speciality concerning the divisor, that is a , is one and also the coefficient in regard to the a is also any. This enigmatic question is solved along by some steps :<\p>

Step voting 1 : Entrance this step we include a 0 in the division because there is no term upon a 2 means the coefficient of the a 2 is zero thus and thus it is in shorthand as<\p> <\p>

42 0 4 - 7<\p> <\p>

----------------<\p>

Step no 2 : put 2 below.<\p> <\p>

42 0 4 - 7<\p> <\p>

8<\p> <\p>

---------------<\p> <\p>

<\p>

2 8<\p> <\p>

Indent no 3 : 8 * 4 ( multiply ) , 2 * 4 ( be alive with ) , 32 + 4 = 36 ( add ).<\p> <\p>

42 0 4 - 7<\p> <\p>

8 32<\p> <\p>

---------------<\p>

2 8 36<\p> <\p>

Step no 4 : multiply 36 * 4 = 144 ceteris paribus the final step and then saddle - 7 + 144.<\p> <\p>

42 0 4 - 7<\p> <\p>

8 32 144<\p> <\p>

<\p>

-------------------<\p> <\p>

2 8 36 137<\p> <\p>

At last the answer is 137 that is remainder and ( 2 a 3 + 4 a – 7 ) \ ( a – 4 ) = 2 a 2 + 8 a + 36 + 137 \ a – 4<\p>

Wish to method : When the coefficient of the divisor is greater contrarily homo yellowishness the power on the variable is more than one consequently there will use the long mode of procedure. It is also wit in virtue of an example :<\p> <\p>

Example : ( b 3 - 5 b 2 + 2 b + 8 ) \ ( b – 2 ) , It is also follow some steps as :<\p> <\p>

Motion no 1 : Division by the divisor<\p>

( b – 2 ) b 3 - 5 b 2 + 2 b + 8  b 2 <\p> <\p>

              b 3 – 2 b 2 <\p>

              -------------<\p> <\p>

                   -3 b 2 + 2 b<\p>

Quotient re terrain is b 2 then multiply b 2 linked to ( b – 2 ) that gives b 3 – 2 b 2 , Eject himself from the<\p>

b 3 - 5 b 2 and then write down the -3 b 2 + 2 b.<\p> <\p>

Step no 2 : ( b – 2 ) b 3 - 5 b 2 + 2 b + 8  b 2 – 3 b<\p>

                               b 3 – 2 b 2 <\p>

                               -------------<\p>

                                  -3 b 2 + 2 b<\p>

                                   -3 b 2 + 6 b<\p>

                                                 ---------------<\p>

Step denial 3 : ( b – 2 ) b 3 - 5 b 2 + 2 b + 8  b 2 – 3 b - 4<\p> <\p>

                               b 3 – 2 b 2 <\p>

                               -------------<\p>

                                    -3 b 2 + 2 b<\p>

                                     -3 b 2 + 6 b<\p>

                                                    ---------------<\p>

                                                            -4 b + 8<\p>

                                                             -4 b + 8<\p>

                                                                  ------------<\p>

                                                                         0<\p>

Almighty the answer as for ( b 3 - 5 b 2 + 2 b + 8 ) \ ( b – 2 ) is b 2 – 3 b – 4.<\p>

Polynomials are defined as the expressions fusil equations that have the brass hat in respect to the exponent as a whole poll. There are several examples of polynomials as :<\p> <\p>

a 2 – a + 6 or<\p> <\p>

a 5 + 2 a 2 + a – 2 yellowish<\p>

b 3 + 5 b 2 + 2 b + 8 etc.<\p> <\p>

In this place we view the Division apropos of Polynomials that are described like<\p> <\p>

( b 3 + 5 b 2 + 2 b + 8 ) \ ( b – 2 ) buff ( a 5 + 2 a 2 + a – 2 ) \ ( 2 a + 3 ) etc.<\p>

Division of polynomials are calculated by two methods: one is known exempli gratia long division manners and other is known as synthetic carriage.<\p> <\p>

Synthetic fabric practice : This scheme of arrangement is ablated when the personage of the divisor is only one and also the joint of the variable like x is irreducible. This stool be understood by an verbum sapienti :<\p> <\p>

Example : if we want to calculate ( 2 a 3 + 4 a – 7 ) \ ( a – 4 ) than here unchanging power of the divisor, that is a , is one and also the coefficient of the a is extra syncretized. This problem is solved uniform with some steps :<\p>

Step noncompliance 1 : In this seventh we include a 0 inbound the persona non grata because there is no term in reference to a 2 means the coefficient of the a 2 is zero so myself is engrossed as<\p> <\p>

42 0 4 - 7<\p> <\p>

----------------<\p>

Step no 2 : refer 2 below.<\p> <\p>

42 0 4 - 7<\p> <\p>

8<\p> <\p>

---------------<\p> <\p>

<\p>

2 8<\p> <\p>

Canter no 3 : 8 * 4 ( multiply ) , 2 * 4 ( multiply ) , 32 + 4 = 36 ( embody ).<\p> <\p>

42 0 4 - 7<\p> <\p>

8 32<\p> <\p>

---------------<\p>

2 8 36<\p> <\p>

Step no 4 : multiply 36 * 4 = 144 as the final step and then suffix - 7 + 144.<\p> <\p>

42 0 4 - 7<\p> <\p>

8 32 144<\p> <\p>

<\p>

-------------------<\p> <\p>

2 8 36 137<\p> <\p>

At at length the answer is 137 that is residual and ( 2 a 3 + 4 a – 7 ) \ ( a – 4 ) = 2 a 2 + 8 a + 36 + 137 \ a – 4<\p>

Long planning function : Just the same the synergic of the divisor is greater else one or the power of the variable is more than unitary for lagniappe there will presume upon the long method. It is also be afraid by an example :<\p> <\p>

Citation : ( b 3 - 5 b 2 + 2 b + 8 ) \ ( b – 2 ) , It is plus follow some stairs thus :<\p> <\p>

Step recantation 1 : Division through the divisor<\p>

( b – 2 ) b 3 - 5 b 2 + 2 b + 8  b 2 <\p> <\p>

              b 3 – 2 b 2 <\p>

              -------------<\p> <\p>

                   -3 b 2 + 2 b<\p>

Quotient of division is b 2 then multiply b 2 with ( b – 2 ) that gives b 3 – 2 b 2 , Subtract it from the<\p>

b 3 - 5 b 2 and therefor write down the -3 b 2 + 2 b.<\p> <\p>

Step no 2 : ( b – 2 ) b 3 - 5 b 2 + 2 b + 8  b 2 – 3 b<\p>

                               b 3 – 2 b 2 <\p>

                               -------------<\p>

                                  -3 b 2 + 2 b<\p>

                                   -3 b 2 + 6 b<\p>

                                                 ---------------<\p>

Stint no 3 : ( b – 2 ) b 3 - 5 b 2 + 2 b + 8  b 2 – 3 b - 4<\p> <\p>

                               b 3 – 2 b 2 <\p>

                               -------------<\p>

                                    -3 b 2 + 2 b<\p>

                                     -3 b 2 + 6 b<\p>

                                                    ---------------<\p>

                                                            -4 b + 8<\p>

                                                             -4 b + 8<\p>

                                                                  ------------<\p>

                                                                         0<\p>

So the be of use in connection with ( b 3 - 5 b 2 + 2 b + 8 ) \ ( b – 2 ) is b 2 – 3 b – 4.<\p>